Question

How do you solve: $\dfrac{{\left( {k - 4} \right)}}{3} = 3$ ?

Answer 1

Hint:The value of the variable k in $\dfrac{{\left( {k - 4} \right)}}{3} = 3$ can be found by using the method of transposition. Method of transposition involves doing the exact same mathematical thing on both sides of an equation with the aim of simplification in mind. This method can be used to solve various algebraic equations like the one given in question with ease.

Complete step by step answer:
We would use the method of transposition to find the value of k in $\dfrac{{\left( {k - 4} \right)}}{3} = 3$. The method of transposition involves doing the exact same operation on both sides of an equation with the aim of bringing like terms together and isolating the variable or the unknown term in order to simplify the equation and finding the value of the required parameter.

Now, in order to find the value of k, we need to isolate the variable from the rest of the parameters.So, we have, $\dfrac{{\left( {k - 4} \right)}}{3} = 3$. Keeping all the terms consisting k to left side of the equation and shifting constant terms to the right side of equation, we get,
$ \Rightarrow $$k - 4 = 3 \times 3$
We must remember to reverse the signs of the terms while shifting the terms from one side of the equation to the other side.
$ \Rightarrow k = 3 \times 3 + 4$

Now, we simplify the calculations keeping in mind the order in which the operations are to be executed.
So, we get,
$ \Rightarrow k = 9 + 4$
So, we simplify the calculations and arrive at our final answer.
$ \Rightarrow k = 13$

Hence, the value of k in $\dfrac{{\left( {k - 4} \right)}}{3} = 3$ is $13$.

Note: If we add, subtract, multiply or divide by the same number on both sides of a given algebraic equation, then both sides will remain equal. The given problem deals with algebraic equations. There is no fixed way of solving a given algebraic equation. Algebraic equations can be solved in various ways. Linear equations in one variable can be solved by the transposition method with ease.