Question

Solve $\dfrac{{3(y - 5)}}{4} - 4y = 3 - \dfrac{{(y - 3)}}{2}$

Answer 1

Hint: The addition is the sum of given two or more than two numbers, or variables and in addition, if we sum the two or more numbers then we obtain a new frame of the number will be found, also in subtraction which is the minus of given two or more than two numbers, but here comes with the condition that in subtraction the greater number sign represented in the number will stay constant example $2 - 3 = - 1$

Complete step by step answer:
Since from given, we are asked to solve $\dfrac{{3(y - 5)}}{4} - 4y = 3 - \dfrac{{(y - 3)}}{2}$ and to find the unknown value $y$
By the multiplication operation, we have $\dfrac{{3y - 15}}{4} - 4y = 3 - \dfrac{{(y - 3)}}{2}$
Again, by the cross-multiplication method, we get $\dfrac{{3y - 15 - 16y}}{4} = \dfrac{{6 - y + 3}}{2}$
By the subtraction method, we have $\dfrac{{ - 15 - 13y}}{4} = \dfrac{{9 - y}}{2}$
Multiplying the number two on the right side and cancel the common terms we get $\dfrac{{ - 15 - 13y}}{4} = \dfrac{{18 - 2y}}{4} \Rightarrow - 15 - 13y = 18 - 2y$
Placing the variables on the left side and numbers on the right side we have $2y - 13y = 18 + 15$
By the subtraction and addition, we get $ - 11y = 33$
Thus, by division, we obtain $y = - \dfrac{{33}}{{11}} \Rightarrow - 3$ which is the required value.
Hence the value of the unknown variable if founded as $y = - 3$ which is in the negative form.

Note:
The other two operations which we used to solve the problem are multiplication and division operations.
Since multiplicand refers to the number multiplied. Also, a multiplier refers to multiplying the first number. Have a look at an example; while multiplying $5 \times 7$the number $5$ is called the multiplicand and the number $7$ is called the multiplier.
The process of the inverse of the multiplication method is called division. Like $x \times y = z$is multiplication thus the division sees as $x = \dfrac{z}{y}$. Like $y = - \dfrac{{33}}{{11}} \Rightarrow - 3$
If we substitute the founded value on the given equation then we will get the answer zero