Question

Solve $4\left( {x + 3} \right) - 2\left( {1 + 3x} \right) = 0$

Answer 1

Hint: The value of x in $4\left( {x + 3} \right) - 2\left( {1 + 3x} \right) = 0$ can be found by using the method of transposition. Method of transposition involves doing the exact same mathematical thing on both sides of an equation with the aim of simplification in mind. This method can be used to solve various algebraic equations like the one given in question with ease.

Complete step by step solution:
We would use the method of transposition to find the value of x in $4\left( {x + 3} \right) - 2\left( {1 + 3x} \right) = 0$.
Now, In order to find the value of x, we need to isolate x from the rest of the parameters.
So, we have, $4\left( {x + 3} \right) - 2\left( {1 + 3x} \right) = 0$
Opening the brackets, we get,
$ \Rightarrow $ $4x + 12 - 2 - 6x = 0$
Now, adding up the like terms, we get,
$ \Rightarrow $ $10 - 2x = 0$
Now, we shift the term consisting of $x$ to the right side of the equation.
We must remember to reverse the signs of the terms while shifting the terms from one side of the equation to the other side.
$ \Rightarrow $ $10 = 2x$
Dividing both the sides of the equation by $2$, we get,
$ \Rightarrow $ $x = \dfrac{{10}}{2}$
Cancelling the common factors in numerator and denominator, we get,
$ \Rightarrow $ $x = 5$
Hence, the value of $x$ in $4\left( {x + 3} \right) - 2\left( {1 + 3x} \right) = 0$ is $5$.

Note:
If we add, subtract, multiply or divide by the same number on both sides of a given algebraic equation, then both sides will remain equal. The given problem deals with algebraic equations. There is no fixed way of solving a given algebraic equation. Algebraic equations can be solved in various ways. Linear equations in one variable can be solved by the transposition method with ease. We must take care while doing the calculations.