Question

How do you solve $3\omega -1-4\omega =4-2\omega $?

Answer 1

Hint: To solve the given equation we will solve the given algebraic operations. We will shift all the constant terms at the right side and keep the variable terms at the left side. Then by simplifying the obtained equation we will get the desired answer.

Complete step-by-step solution:
We have been given an equation $3\omega -1-4\omega =4-2\omega $.
We have to solve the given equation and find the value of the unknown variable.
The given equation is a linear equation in one variable. A linear equation in one variable has only one solution. By solving the given equation we have to find the value of an unknown variable i. e. $\omega $.
To solve the equation first we will shift all constant terms at the right side. Then we will get
$\Rightarrow 3\omega -4\omega =4-2\omega +1$
Now, shifting the variable terms at the left side we will get
\[\Rightarrow 3\omega -4\omega +2\omega =4+1\]
Now, simplifying the above obtained equation we will get
\[\Rightarrow \omega =5\]
Hence on solving the given equation we get the value of \[\omega \]as 5.

Note: As the given equation is a linear equation in variable $\omega $. Students may treat the variable as omega the square root of unity and solve accordingly. But in this equation $\omega $ is the simple variable just like x, y, z. We can also verify the answer by putting the obtained value in the given equation.