
Solve $3\left( {2 - x} \right) + 6x = 18$?
Answer
547.2k+ views
Hint: The given equation is the equation in one variable. We have to seek out the worth of the variable. For that, we have to open the bracket and multiply the terms by the coefficient and simplify. After that divide both sides of the equation by the coefficient of the variable. The value of the variable will be the desired result.
Complete step by step answer:
The given equation is the equation in one variable.
Let us know what's the equation in one variable.
When you have a variable of a maximum of one order in an equation, then it's referred to as an equation in one variable. The linear equation is usually expressed in the form of \[ax + b = 0\]. Here a and b are two integers and the solution of x can be only one. The value of a and b can never be adequate to 0.
For Example, \[5x + 6 = 10\] is an equation that is linear and has only a single variable in it. The only solution to this equation would be $x = \dfrac{4}{5}$.
Now the given equation is $3\left( {2 - x} \right) + 6x = 18$.
Open the bracket and multiply the term by the coefficient,
$ \Rightarrow 6 - 3x + 6x = 18$
Move the constant part on one side,
$ \Rightarrow - 3x + 6x = 18 - 6$
Simplify the terms,
$ \Rightarrow 3x = 12$
Divide both sides by 3,
$\therefore x = 4$
Hence, the value of $x$ is 4.
Note: When you have to solve an equation that has always only one solution, then the steps given below are followed.
Step 1: Find the LCM. In case any fractions exist, clear them.
Step 2: In this step simplification of both sides of the equation happens.
Step 3: Here, you will be isolating the variable on one side.
Step 4: You will verify the obtained result.
Complete step by step answer:
The given equation is the equation in one variable.
Let us know what's the equation in one variable.
When you have a variable of a maximum of one order in an equation, then it's referred to as an equation in one variable. The linear equation is usually expressed in the form of \[ax + b = 0\]. Here a and b are two integers and the solution of x can be only one. The value of a and b can never be adequate to 0.
For Example, \[5x + 6 = 10\] is an equation that is linear and has only a single variable in it. The only solution to this equation would be $x = \dfrac{4}{5}$.
Now the given equation is $3\left( {2 - x} \right) + 6x = 18$.
Open the bracket and multiply the term by the coefficient,
$ \Rightarrow 6 - 3x + 6x = 18$
Move the constant part on one side,
$ \Rightarrow - 3x + 6x = 18 - 6$
Simplify the terms,
$ \Rightarrow 3x = 12$
Divide both sides by 3,
$\therefore x = 4$
Hence, the value of $x$ is 4.
Note: When you have to solve an equation that has always only one solution, then the steps given below are followed.
Step 1: Find the LCM. In case any fractions exist, clear them.
Step 2: In this step simplification of both sides of the equation happens.
Step 3: Here, you will be isolating the variable on one side.
Step 4: You will verify the obtained result.
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