Question

Solve: $2{x^2} + 3x - 90 = 0$

Answer 1

Hint: Here we are asked to solve the given quadratic equation that is we have to find its roots. Since it is an equation of order two it will have two roots. The roots of a quadratic equation can be found by using the quadratic formula.
Formula: The formula that we need to know before solving the problem:
Let \[a{x^2} + bx + c = 0\] be a quadratic equation then the roots of this equation are given by \[\dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}\].

Complete step by step answer:
Given $2{x^2} + 3x - 90 = 0$ is a quadratic equation and we have to find its roots.
We know that the number of roots of an equation is equal to its degree. Here the degree of the given equation is two thus this equation will have two roots.
The roots of a quadratic equation can be found by using the formula \[\dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}\] where \[a\] - coefficient of the term \[{x^2}\], \[b\] - coefficient of the term \[x\], and \[c\] - constant term.
First, let us collect the required terms for the formula from the given quadratic equation to solve it.
From the given equation $2{x^2} + 3x - 90 = 0$, we have \[a = 2\], \[b = 3\], and \[c = - 90\].
On substituting these terms in the formula, we get
\[x = \dfrac{{ - \left( 3 \right) \pm \sqrt {{{\left( 3 \right)}^2} - 4\left( 2 \right)\left( { - 90} \right)} }}{{2\left( 2 \right)}}\]
On simplifying this we get
\[x = \dfrac{{ - 3 \pm \sqrt {9 + 720} }}{4}\]
On further simplification we get
\[x = \dfrac{{ - 3 \pm \sqrt {729} }}{4}\]
    \[ = \dfrac{{ - 3 \pm 27}}{4}\]
\[ \Rightarrow x = \dfrac{{ - 3 + 27}}{4}\] and \[ \Rightarrow x = \dfrac{{ - 3 - 27}}{4}\]
On solving the above, we get
\[ \Rightarrow x = 6\] and \[ \Rightarrow x = - \dfrac{{15}}{2}\]
Thus, we got the roots of the given quadratic equation that is \[ \Rightarrow x = 6\] and \[ \Rightarrow x = - \dfrac{{15}}{2}\]

Note:
The roots of the equation are nothing but the possible value of the unknown variable in that equation. Also, the number of roots of an equation depends on its degree. The degree of an equation is the highest power of the unknown variable in that equation.
Also, in the quadratic equation, the $a = 0$ is never possible, because then it will be a linear equation.