Question

Solve $12 + \left\{ {6 - \left( {3 - 2} \right) + 4} \right\} - \left( {25 - 5} \right)$

Answer 1

Hint: We will simplify the question using the BODMAS rule. We will first simplify the brackets. We will first add and then subtract to simplify the given expression. We have to use the operations in the same order as given in the BODMAS.

Complete step-by-step answer:
We have to find the value of $12 + \left\{ {6 - \left( {3 - 2} \right) + 4} \right\} - \left( {25 - 5} \right)$.
We will BODMAS rule to find the value of $12 + \left\{ {6 - \left( {3 - 2} \right) + 4} \right\} - \left( {25 - 5} \right)$
In BODMAS rule, B stands for brackets, O stands for order of power, D represents division, M is multiplication and S represents subtraction.
We apply the operations in the order as given in the word BODMAS.
Hence, we will first solve the brackets.
On solving brackets we, get,
$12 + \left\{ {6 - 1 + 4} \right\} - 20$
Now, we will solve the inner brackets using the BODMAS rule, that is we will add first and then subtract the terms.
Therefore, we will have,
$12 + \left\{ {10 - 1} \right\} - 20$
$12 + 9 - 20$
We will now solve this again using BODMAS rule,
$\Rightarrow$ $21 - 20 = 1$
Hence, the correct answer is 1.

Note: We have to apply BODMAS everywhere when there are more than one operations. The rule of BODMAS can be applied more than once in one question. Here, we had only three operations, brackets, addition and subtraction.