
How do you solve $10x - 8 + 2x\left( 3 \right) = 4\left( {x - 8} \right) + 9\left( {3 - x} \right)$?
Answer
545.1k+ views
Hint: First step is to apply distributivity property in the given equation, i.e., multiplying each addend individually by the number and then adding the products together. Next, we have to isolate the variable terms on one side by performing the same mathematical operations on both sides of the equation. Next step is to isolate the constant terms on the other side by performing the same mathematical operations on both sides of the equation. Next step is to make the coefficient of the variable equal to $1$ using multiplication or division property.
Complete step by step solution:
Given equation is $10x - 8 + 2x\left( 3 \right) = 4\left( {x - 8} \right) + 9\left( {3 - x} \right)$.
We have to find the value of $x$.
First, we have to apply the distributive property in the given equation, i.e., multiplying each addend individually by the number and then adding the products together.
$10x - 8 + 2x\left( 3 \right) = 4\left( x \right) + 4\left( { - 8} \right) + 9\left( 3 \right) + 9\left( { - x} \right)$
It can be written as
$ \Rightarrow 10x - 8 + 6x = 4x - 32 + 27 - 9x$
Add $10x$ and $6x$, add $4x$ and $ - 9x$, add $ - 32$ and $27$, we get
$ \Rightarrow 16x - 8 = - 5x - 5$
Now we have to isolate the variable terms on one side by performing the same mathematical operations on both sides of the equation.
So, adding $5x$ to both sides of the equation, we get
$ \Rightarrow 16x - 8 + 5x = - 5x - 5 + 5x$
$ \Rightarrow 21x - 8 = - 5$
Next step is to isolate the constant terms on the other side by performing the same mathematical operations on both sides of the equation.
So, adding $8$ to both sides of the equation, we get
$ \Rightarrow 21x - 8 + 8 = - 5 + 8$
$ \Rightarrow 21x = 3$
Now we have to make the coefficient of the variable equal to $1$ using multiplication or division property.
So, dividing both sides of equation by $21$, we get
$\dfrac{{21x}}{{21}} = \dfrac{3}{{21}}$
It can be written as
$x = \dfrac{1}{7}$
Therefore, $x = \dfrac{1}{7}$ is the solution of $10x - 8 + 2x\left( 3 \right) = 4\left( {x - 8} \right) + 9\left( {3 - x} \right)$.
Note: 1. An algebraic equation is an equation involving variables. It has an equality sign. The expression on the left of the equality sign is the Left Hand Side (LHS). The expression on the right of the equality sign is the Right Hand Side (RHS).
2. In an equation the values of the expressions on the LHS and RHS are equal. This happens to be true only for certain values of the variable. These values are the solutions of the equation.
Complete step by step solution:
Given equation is $10x - 8 + 2x\left( 3 \right) = 4\left( {x - 8} \right) + 9\left( {3 - x} \right)$.
We have to find the value of $x$.
First, we have to apply the distributive property in the given equation, i.e., multiplying each addend individually by the number and then adding the products together.
$10x - 8 + 2x\left( 3 \right) = 4\left( x \right) + 4\left( { - 8} \right) + 9\left( 3 \right) + 9\left( { - x} \right)$
It can be written as
$ \Rightarrow 10x - 8 + 6x = 4x - 32 + 27 - 9x$
Add $10x$ and $6x$, add $4x$ and $ - 9x$, add $ - 32$ and $27$, we get
$ \Rightarrow 16x - 8 = - 5x - 5$
Now we have to isolate the variable terms on one side by performing the same mathematical operations on both sides of the equation.
So, adding $5x$ to both sides of the equation, we get
$ \Rightarrow 16x - 8 + 5x = - 5x - 5 + 5x$
$ \Rightarrow 21x - 8 = - 5$
Next step is to isolate the constant terms on the other side by performing the same mathematical operations on both sides of the equation.
So, adding $8$ to both sides of the equation, we get
$ \Rightarrow 21x - 8 + 8 = - 5 + 8$
$ \Rightarrow 21x = 3$
Now we have to make the coefficient of the variable equal to $1$ using multiplication or division property.
So, dividing both sides of equation by $21$, we get
$\dfrac{{21x}}{{21}} = \dfrac{3}{{21}}$
It can be written as
$x = \dfrac{1}{7}$
Therefore, $x = \dfrac{1}{7}$ is the solution of $10x - 8 + 2x\left( 3 \right) = 4\left( {x - 8} \right) + 9\left( {3 - x} \right)$.
Note: 1. An algebraic equation is an equation involving variables. It has an equality sign. The expression on the left of the equality sign is the Left Hand Side (LHS). The expression on the right of the equality sign is the Right Hand Side (RHS).
2. In an equation the values of the expressions on the LHS and RHS are equal. This happens to be true only for certain values of the variable. These values are the solutions of the equation.
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