What is the slope and y-intercept of the line $ x = - 5 $ ?
Answer
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Hint: We know the equation of a line passing through a point and having a slope ‘m’ and with ‘y’ intercept as ‘c’ is given by $ y = mx + c $ . Here, (x, y) is a variable. We convert the given equation to the slope intercept form. Then comparing the simplified equation with the equation of slope intercept we will get the desired result.
Complete step-by-step answer:
In the given problem, we are required to find the slope and intercept of the line whose equation is given to us as $ x = - 5 $ .
The slope intercept form of the equation of a line is $ y = mx + c $ where slope of line is given by ‘m’ and y-intercept is given by ‘c’.
So, first we write the equation with the coefficient of y term being zero.
We get, $ 1x + 0y = - 5 $
Shifting term consisting x to the right side of the equation,
$ \Rightarrow 0y = - x - 5 $
Isolating y so as to convert the equation of line to slope and intercept form, we get,
$ \Rightarrow y = \dfrac{{\left( { - x - 5} \right)}}{0} $
Now, we can directly start comparing the equation of the given line with the slope and intercept form of a line and get the values of slope and intercept of the line.
Therefore, On comparing the equation of the line $ y = \left( { - \dfrac{1}{0}x - \dfrac{5}{0}} \right) $ given to us and the slope intercept form of the line $ y = mx + c $ , we get,
Slope of the line $ = m = - \dfrac{1}{0} $ . hence, the slope of the line is undefined since division by zero is undefined.
Also, y-intercept $ = c = - \dfrac{5}{0} $ . Hence, the y-intercept is also undefined.
We know that the line such as the one given in the question itself is parallel to y-axis. So, the slope of such lines is undefined. Also, the line being parallel to the y-axis does not meet the y-axis at any point. So, the y intercept is also undefined.
Note: ‘y’ intercept is defined as a line or a curve crosses the y-axis of a graph. In other words the value of ‘y’ at ‘x’ is equal to zero. Hence, the y intercept of a line can also be found by putting the value of x as zero. Slope of a line is the inclination of the straight line with positive x-axis.
Complete step-by-step answer:
In the given problem, we are required to find the slope and intercept of the line whose equation is given to us as $ x = - 5 $ .
The slope intercept form of the equation of a line is $ y = mx + c $ where slope of line is given by ‘m’ and y-intercept is given by ‘c’.
So, first we write the equation with the coefficient of y term being zero.
We get, $ 1x + 0y = - 5 $
Shifting term consisting x to the right side of the equation,
$ \Rightarrow 0y = - x - 5 $
Isolating y so as to convert the equation of line to slope and intercept form, we get,
$ \Rightarrow y = \dfrac{{\left( { - x - 5} \right)}}{0} $
Now, we can directly start comparing the equation of the given line with the slope and intercept form of a line and get the values of slope and intercept of the line.
Therefore, On comparing the equation of the line $ y = \left( { - \dfrac{1}{0}x - \dfrac{5}{0}} \right) $ given to us and the slope intercept form of the line $ y = mx + c $ , we get,
Slope of the line $ = m = - \dfrac{1}{0} $ . hence, the slope of the line is undefined since division by zero is undefined.
Also, y-intercept $ = c = - \dfrac{5}{0} $ . Hence, the y-intercept is also undefined.
We know that the line such as the one given in the question itself is parallel to y-axis. So, the slope of such lines is undefined. Also, the line being parallel to the y-axis does not meet the y-axis at any point. So, the y intercept is also undefined.
Note: ‘y’ intercept is defined as a line or a curve crosses the y-axis of a graph. In other words the value of ‘y’ at ‘x’ is equal to zero. Hence, the y intercept of a line can also be found by putting the value of x as zero. Slope of a line is the inclination of the straight line with positive x-axis.
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