
How do you simplify this equation $\left( 3x+5y \right)\left( 3x-5y \right)$
Answer
538.8k+ views
Hint: Now we want to simplify the given expression. To do so we will first use distributive property which says $c\left( a+b \right)=ca+cb$ . Then we will rearrange the terms using commutative property. Now again we will use the distributive property and simplify the equation. Hence we get the required expression.
Complete step by step solution:
Now to expand the term we will first understand properties of real numbers.
First let us understand commutative property.
Commutative property for addition is given as $a+b=b+a$ similarly we commutative property for multiplication as $ab=ba$ .
Now associativity for addition is defined $a+\left( b+c \right)=\left( a+b \right)+c$ and the associativity for multiplication defined as $\left( a.b \right).c=a.\left( b.c \right)$ .
Now let us understand the distributive property.
Distributive property is defined as $a.\left( b+c \right)=a.b+a.c$ .
Now consider the given expression $\left( 3x+5y \right)\left( 3x-5y \right)$
Now in the given expression we have multiplication of two terms. First we will open one bracket using distributive property. Now according to distributive property we have $a.\left( b+c \right)=a.b+a.c$ So let $a=3x+5y$, $b=3x$ and $c=-5y$. Hence we get the expansion as,
$\Rightarrow \left( 3x+5y \right)\left( 3x \right)+\left( 3x+5y \right)\left( -5y \right)$
Now using commutative property of multiplication we have,
$\Rightarrow \left( 3x \right)\left( 3x+5y \right)+\left( -5y \right)\left( 3x+5y \right)$
Now again using distributive property we get,
$\Rightarrow \left( 3x \right)\left( 3x \right)+\left( 3x \right)\left( 5y \right)+\left( -5y \right)\left( 3x \right)+\left( -5y \right)\left( 5y \right)$
Now we know that $\left( 3x \right)\left( 3x \right)=9{{x}^{2}}$ , $\left( 3x \right)\left( 5y \right)=15xy$ and $\left( -5y \right)\left( 5y \right)=25{{y}^{2}}$
Hence on simplifying the above equation using the obtained values we get,
$\Rightarrow 9{{x}^{2}}+15xy-15xy-25{{y}^{2}}$
Now we know that 15xy – 15xy = 0, hence using this we get the equation as,
$\Rightarrow 9{{x}^{2}}-25{{y}^{2}}$
Hence the simplified expression of the given expression is $9{{x}^{2}}-25{{y}^{2}}$
Note:
Now note that the given equation is in the form of $\left( a+b \right)\left( a-b \right)$ . now we know that the formula for $\left( {{a}^{2}}-{{b}^{2}} \right)$ is given by $\left( a-b \right)\left( a+b \right)$ Hence using this formula we can easily expand the term. Hence we get $\left( 3x+5y \right)\left( 3x-5y \right)={{\left( 3x \right)}^{2}}-{{\left( 5y \right)}^{2}}$ . Now on taking the square of term we will get the required solution.
Complete step by step solution:
Now to expand the term we will first understand properties of real numbers.
First let us understand commutative property.
Commutative property for addition is given as $a+b=b+a$ similarly we commutative property for multiplication as $ab=ba$ .
Now associativity for addition is defined $a+\left( b+c \right)=\left( a+b \right)+c$ and the associativity for multiplication defined as $\left( a.b \right).c=a.\left( b.c \right)$ .
Now let us understand the distributive property.
Distributive property is defined as $a.\left( b+c \right)=a.b+a.c$ .
Now consider the given expression $\left( 3x+5y \right)\left( 3x-5y \right)$
Now in the given expression we have multiplication of two terms. First we will open one bracket using distributive property. Now according to distributive property we have $a.\left( b+c \right)=a.b+a.c$ So let $a=3x+5y$, $b=3x$ and $c=-5y$. Hence we get the expansion as,
$\Rightarrow \left( 3x+5y \right)\left( 3x \right)+\left( 3x+5y \right)\left( -5y \right)$
Now using commutative property of multiplication we have,
$\Rightarrow \left( 3x \right)\left( 3x+5y \right)+\left( -5y \right)\left( 3x+5y \right)$
Now again using distributive property we get,
$\Rightarrow \left( 3x \right)\left( 3x \right)+\left( 3x \right)\left( 5y \right)+\left( -5y \right)\left( 3x \right)+\left( -5y \right)\left( 5y \right)$
Now we know that $\left( 3x \right)\left( 3x \right)=9{{x}^{2}}$ , $\left( 3x \right)\left( 5y \right)=15xy$ and $\left( -5y \right)\left( 5y \right)=25{{y}^{2}}$
Hence on simplifying the above equation using the obtained values we get,
$\Rightarrow 9{{x}^{2}}+15xy-15xy-25{{y}^{2}}$
Now we know that 15xy – 15xy = 0, hence using this we get the equation as,
$\Rightarrow 9{{x}^{2}}-25{{y}^{2}}$
Hence the simplified expression of the given expression is $9{{x}^{2}}-25{{y}^{2}}$
Note:
Now note that the given equation is in the form of $\left( a+b \right)\left( a-b \right)$ . now we know that the formula for $\left( {{a}^{2}}-{{b}^{2}} \right)$ is given by $\left( a-b \right)\left( a+b \right)$ Hence using this formula we can easily expand the term. Hence we get $\left( 3x+5y \right)\left( 3x-5y \right)={{\left( 3x \right)}^{2}}-{{\left( 5y \right)}^{2}}$ . Now on taking the square of term we will get the required solution.
Recently Updated Pages
Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
The shortest day of the year in India

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

