Simplify the following expression and write its value in simpler numbers: \[\dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }} - \dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }}\]
Answer
681.3k+ views
Hint: Recall the definition for rational and irrational numbers. Use rationalization to convert the denominator of each term into a rational number and then evaluate the expression.
Complete step by step solution:
We, now, rationalise \[\dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }}\] by multiplying both the numerator and the denominator by \[7 + 4\sqrt 3 \]. Hence, we have as follows:
$\Rightarrow$ \[\dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }} = \dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }} \times \dfrac{{7 + 4\sqrt 3 }}{{7 + 4\sqrt 3 }}\]
Simplifying using \[(a + b)(a - b) = {a^2} + {b^2}\], we get:
$\Rightarrow$ \[\dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }} = \dfrac{{35 + 7\sqrt 3 + 20\sqrt 3 + 12}}{{{7^2} - {{\left( {4\sqrt 3 } \right)}^2}}}\]
$\Rightarrow$ \[\dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }} = \dfrac{{47 + 27\sqrt 3 }}{{49 - 48}}\]
$\Rightarrow$ \[\dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }} = 47 + 27\sqrt 3 .........(1)\]
We, now, rationalise \[\dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }}\] by multiplying both the numerator and the denominator by \[7 - 4\sqrt 3 \]. Hence, we have as follows:
$\Rightarrow$ \[\dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }} = \dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }} \times \dfrac{{7 - 4\sqrt 3 }}{{7 - 4\sqrt 3 }}\]
Simplifying using \[(a + b)(a - b) = {a^2} + {b^2}\], we get:
$\Rightarrow$ \[\dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }} = \dfrac{{35 - 7\sqrt 3 - 20\sqrt 3 + 12}}{{{7^2} - {{\left( {4\sqrt 3 } \right)}^2}}}\]
$\Rightarrow$ \[\dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }} = \dfrac{{47 - 27\sqrt 3 }}{{49 - 48}}\]
$\Rightarrow$ \[\dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }} = 47 - 27\sqrt 3 .........(2)\]
Using equations (1) and (2), we have:
$\Rightarrow$ \[\dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }} - \dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }} = 47 + 27\sqrt 3 - (47 - 27\sqrt 3 )\]
$\Rightarrow$ \[\dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }} - \dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }} = 47 + 27\sqrt 3 - 47 + 27\sqrt 3 \]
$\Rightarrow$ \[\dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }} - \dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }} = 54\sqrt 3 \]
Hence, the answer is \[54\sqrt 3 \].
Note: When you substitute the rationalized terms do not forget the negative sign in between the terms which might end up with answer 94, which is wrong.
Complete step by step solution:
We, now, rationalise \[\dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }}\] by multiplying both the numerator and the denominator by \[7 + 4\sqrt 3 \]. Hence, we have as follows:
$\Rightarrow$ \[\dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }} = \dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }} \times \dfrac{{7 + 4\sqrt 3 }}{{7 + 4\sqrt 3 }}\]
Simplifying using \[(a + b)(a - b) = {a^2} + {b^2}\], we get:
$\Rightarrow$ \[\dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }} = \dfrac{{35 + 7\sqrt 3 + 20\sqrt 3 + 12}}{{{7^2} - {{\left( {4\sqrt 3 } \right)}^2}}}\]
$\Rightarrow$ \[\dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }} = \dfrac{{47 + 27\sqrt 3 }}{{49 - 48}}\]
$\Rightarrow$ \[\dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }} = 47 + 27\sqrt 3 .........(1)\]
We, now, rationalise \[\dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }}\] by multiplying both the numerator and the denominator by \[7 - 4\sqrt 3 \]. Hence, we have as follows:
$\Rightarrow$ \[\dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }} = \dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }} \times \dfrac{{7 - 4\sqrt 3 }}{{7 - 4\sqrt 3 }}\]
Simplifying using \[(a + b)(a - b) = {a^2} + {b^2}\], we get:
$\Rightarrow$ \[\dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }} = \dfrac{{35 - 7\sqrt 3 - 20\sqrt 3 + 12}}{{{7^2} - {{\left( {4\sqrt 3 } \right)}^2}}}\]
$\Rightarrow$ \[\dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }} = \dfrac{{47 - 27\sqrt 3 }}{{49 - 48}}\]
$\Rightarrow$ \[\dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }} = 47 - 27\sqrt 3 .........(2)\]
Using equations (1) and (2), we have:
$\Rightarrow$ \[\dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }} - \dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }} = 47 + 27\sqrt 3 - (47 - 27\sqrt 3 )\]
$\Rightarrow$ \[\dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }} - \dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }} = 47 + 27\sqrt 3 - 47 + 27\sqrt 3 \]
$\Rightarrow$ \[\dfrac{{5 + \sqrt 3 }}{{7 - 4\sqrt 3 }} - \dfrac{{5 - \sqrt 3 }}{{7 + 4\sqrt 3 }} = 54\sqrt 3 \]
Hence, the answer is \[54\sqrt 3 \].
Note: When you substitute the rationalized terms do not forget the negative sign in between the terms which might end up with answer 94, which is wrong.
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