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# Simplify the equation and find its value :- $({5^0}{\text{x}}{{\text{3}}^0} + {7^0}{\text{x}}{{\text{8}}^0}){\text{x}}{{\text{4}}^0}$.

Last updated date: 19th Mar 2023
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Hint: In order to solve this problem we have to know that anything raised to the power zero is one. This will take you to the correct solution of the problem.

The given equation is $({5^0}{\text{x}}{{\text{3}}^0} + {7^0}{\text{x}}{{\text{8}}^0}){\text{x}}{{\text{4}}^0}$.
Therefore we can do ${5^0} = 1,\,{3^0} = 1,\,{7^0} = 1,\,{8^0} = 1,\,{4^0} = 1$