Simplify $\sqrt {\left( {1 + \sin 2x} \right)} $.
Answer
561.6k+ views
Hint: Here we are given an expression and we need to simplify it. We can note that the given expression is trigonometric. The term simplify refers to make it easier or simpler. So, we need to convert our given expression into a simpler manner. To solve a trigonometric expression, we need to apply some appropriate trigonometric identities and algebraic identities.
Formula used:
The following formulas are to be used to solve the given problem.
a) ${\sin ^2}x + {\cos ^2}x = 1$
b) $\sin 2x = 2\sin x\cos x$
c)${\left( {a + b} \right)^2} = {a^2} + {b^2} + 2ab$
Complete step by step solution:
The given expression is $\sqrt {\left( {1 + \sin 2x} \right)} $.
Here, we need to substitute the known formulae in the expression.
That is in the place of $1$, we shall substitute the formula ${\sin ^2}x + {\cos ^2}x = 1$
Similarly in the place of $\sin 2x$ , we have to replace the formula $\sin 2x = 2\sin x\cos x$
Hence, we will obtain the following solution.
\[\sqrt {\left( {1 + \sin 2x} \right)} = \sqrt {\left( {{{\sin }^2}x + {{\cos }^2}x + \sin 2x} \right)} \] (Here we have replaced $1$by${\sin ^2}x + {\cos ^2}x$)
\[ = \sqrt {\left( {{{\sin }^2}x + {{\cos }^2}x + 2\sin x\cos x} \right)} \] (Here we substituted $2\sin x\cos x$)
Now, we are able to note that the resultant expression inside the brackets is in the form ${a^2} + {b^2} + 2ab$.
To simplify this expression, we shall apply the formula ${\left( {a + b} \right)^2} = {a^2} + {b^2} + 2ab$.
Therefore we get\[\sqrt {\left( {1 + \sin 2x} \right)} = \sqrt {{{\left( {\sin x + \cos x} \right)}^2}} \] …..$\left( 1 \right)$ (Here $a = \sin x$ and$b = \cos x$)
Also, it is a well-known fact that the square root and the square of any number can cancel each other. For instance, if we consider $\sqrt {{{\left( 3 \right)}^2}} $ then our required answer will be $3$ .
Hence, $\left( 1 \right)$we get\[\sqrt {\left( {1 + \sin 2x} \right)} = \sin x + \cos x\] that is the required solution.
Note:
First of all, we need to check whether the given expression whether will be trigonometric or algebraic. If we are given an algebraic expression, there is no need to use trigonometric identities. But in solving a trigonometric expression, we may need to apply both algebraic and trigonometric identities.
Formula used:
The following formulas are to be used to solve the given problem.
a) ${\sin ^2}x + {\cos ^2}x = 1$
b) $\sin 2x = 2\sin x\cos x$
c)${\left( {a + b} \right)^2} = {a^2} + {b^2} + 2ab$
Complete step by step solution:
The given expression is $\sqrt {\left( {1 + \sin 2x} \right)} $.
Here, we need to substitute the known formulae in the expression.
That is in the place of $1$, we shall substitute the formula ${\sin ^2}x + {\cos ^2}x = 1$
Similarly in the place of $\sin 2x$ , we have to replace the formula $\sin 2x = 2\sin x\cos x$
Hence, we will obtain the following solution.
\[\sqrt {\left( {1 + \sin 2x} \right)} = \sqrt {\left( {{{\sin }^2}x + {{\cos }^2}x + \sin 2x} \right)} \] (Here we have replaced $1$by${\sin ^2}x + {\cos ^2}x$)
\[ = \sqrt {\left( {{{\sin }^2}x + {{\cos }^2}x + 2\sin x\cos x} \right)} \] (Here we substituted $2\sin x\cos x$)
Now, we are able to note that the resultant expression inside the brackets is in the form ${a^2} + {b^2} + 2ab$.
To simplify this expression, we shall apply the formula ${\left( {a + b} \right)^2} = {a^2} + {b^2} + 2ab$.
Therefore we get\[\sqrt {\left( {1 + \sin 2x} \right)} = \sqrt {{{\left( {\sin x + \cos x} \right)}^2}} \] …..$\left( 1 \right)$ (Here $a = \sin x$ and$b = \cos x$)
Also, it is a well-known fact that the square root and the square of any number can cancel each other. For instance, if we consider $\sqrt {{{\left( 3 \right)}^2}} $ then our required answer will be $3$ .
Hence, $\left( 1 \right)$we get\[\sqrt {\left( {1 + \sin 2x} \right)} = \sin x + \cos x\] that is the required solution.
Note:
First of all, we need to check whether the given expression whether will be trigonometric or algebraic. If we are given an algebraic expression, there is no need to use trigonometric identities. But in solving a trigonometric expression, we may need to apply both algebraic and trigonometric identities.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

