
How do you simplify $\ln \left( {\dfrac{1}{e}} \right)$?
Answer
555.9k+ views
Hint: Here we will use the formula of the natural logarithm and get the value which is required of the function $\ln \left( {\dfrac{1}{e}} \right)$ and the formula we can use will be $\ln \left( {\dfrac{a}{b}} \right) = \ln a - \ln b$ and we must know that $\ln $ represents the natural log and its base is always $e$ and also that the log of $1 = 0$.
Complete step-by-step answer:
Here we are given to find the value of $\ln \left( {\dfrac{1}{e}} \right)$
So to solve it, we must know that $\ln $ represents the natural log and its base is always $e$ and also that the log of $1 = 0$
Also we must know that property of logarithm that ${\log _a}a = 1$$ - - - - (1)$
Which means that when base and the number whose log is to be found are equal, then the value of it is always equal to $1$
So we can write the function
$\ln \left( {\dfrac{1}{e}} \right)$$ = \ln 1 - \ln e$
As we know that $\ln \left( {\dfrac{a}{b}} \right) = \ln a - \ln b$
Also we know that $\ln $ represents the natural log and its base is always $e$ and also that the log of $1 = 0$
So we can say that
$\ln \left( {\dfrac{1}{e}} \right)$$ = \ln 1 - \ln e$
$ = 0 - {\log _e}e$
So according to the equation (1) we get that:
$\ln \left( {\dfrac{1}{e}} \right)$$ = \ln 1 - \ln e$$ = 0 - 1 = - 1$
So we get that the value of the given function which is $\ln \left( {\dfrac{1}{e}} \right)$ as $ - 1$
Hence we can say that in order to solve such problems which contain the logarithm, we must know the properties of the logarithm and the natural log.
So we can say that properties are to be known to solve such problems.
Note: In order to solve such problems where we have to simplify the properties of the logarithm and the natural log must be known to us like:
$\ln \left( {\dfrac{a}{b}} \right) = \ln a - \ln b$
$\ln \left( {ab} \right) = \ln a + \ln b$
Complete step-by-step answer:
Here we are given to find the value of $\ln \left( {\dfrac{1}{e}} \right)$
So to solve it, we must know that $\ln $ represents the natural log and its base is always $e$ and also that the log of $1 = 0$
Also we must know that property of logarithm that ${\log _a}a = 1$$ - - - - (1)$
Which means that when base and the number whose log is to be found are equal, then the value of it is always equal to $1$
So we can write the function
$\ln \left( {\dfrac{1}{e}} \right)$$ = \ln 1 - \ln e$
As we know that $\ln \left( {\dfrac{a}{b}} \right) = \ln a - \ln b$
Also we know that $\ln $ represents the natural log and its base is always $e$ and also that the log of $1 = 0$
So we can say that
$\ln \left( {\dfrac{1}{e}} \right)$$ = \ln 1 - \ln e$
$ = 0 - {\log _e}e$
So according to the equation (1) we get that:
$\ln \left( {\dfrac{1}{e}} \right)$$ = \ln 1 - \ln e$$ = 0 - 1 = - 1$
So we get that the value of the given function which is $\ln \left( {\dfrac{1}{e}} \right)$ as $ - 1$
Hence we can say that in order to solve such problems which contain the logarithm, we must know the properties of the logarithm and the natural log.
So we can say that properties are to be known to solve such problems.
Note: In order to solve such problems where we have to simplify the properties of the logarithm and the natural log must be known to us like:
$\ln \left( {\dfrac{a}{b}} \right) = \ln a - \ln b$
$\ln \left( {ab} \right) = \ln a + \ln b$
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

