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How do you simplify $ - \left( {\dfrac{{2x}}{{ - xy}}} \right) $ completely ?

Answer
VerifiedVerified
546.3k+ views
Hint: To simplify this question , we need to solve it step by step . We will cancel out the like terms in the numerator and the denominator for simplification . . We should know that the question having -1 in the numerator and the denominator is considered and cancelled as to be making unity or positive . Also make the group of like variables together . Here we have two variables having in the numerator and the denominator , we will rewrite it similarly making groups of the same variable and try to simplify by cancelling out the common factors to get the required result .

Complete step-by-step answer:
In order to solve the expression , write it the way it is given and then arrange it –
 $\Rightarrow - \left( {\dfrac{{2x}}{{ - xy}}} \right) $
We can rewrite the negative sign as -1 ,
 $\Rightarrow \left( {\dfrac{{ - 1 \times 2x}}{{ - 1 \times xy}}} \right) $
Now simplify by cancelling out the common factors ,
 $\Rightarrow \left( {\dfrac{{2x}}{{xy}}} \right) $
Now we can cancel out the same variable in the denominator and the numerator and solving the question further -
 $ $ $ \left( {\dfrac{2}{y}} \right) $
Now apply the formula of $ = \dfrac{1}{x} = {x^{ - 1}} $
 $\Rightarrow 2{y^{ - 1}} $
Therefore , the solution to this question is $ 2{y^{ - 1}} $ .
So, the correct answer is “ $ 2{y^{ - 1}} $ ”.

Note: Always remember you can perform calculations only between like terms .
The expression is having hidden multiplication when written altogether .
Make sure the calculation in the question is done correctly.
To calculate the simplified answer try to break out the steps from the question.
Always check the required formula exponent rule and try to cancel out the common factors.
If the base of the exponent number is prime, we cannot simplify the question further and answer is obtained by simply calculating the exponent value.
Do not forget to verify the exponents solved correctly .
Always try to cancel out the similar terms for the solution of simplification .
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