Question

How do you simplify $\left( 6+32 \right)\left( 4-2 \right)$ using order of operations?

Answer 1

Hint: For this we need to simplify the given value by using the order of operations. For this we will first list all the operations we have in the given value. After that we will use the BODMAS rule to identify the order of operation. Once we have the order of operations, we will perform the operations in the order to get the required result.

Complete step by step solution:
Given value, $\left( 6+32 \right)\left( 4-2 \right)$.
In the above value, we can observe only one operation which is brackets and, in the brackets, we have different operations which are not considered. As we have only one operation, we are going to simplify the brackets first.
Simplifying the value $\left( 6+32 \right)$. We know that the value of $6+32$ is $38$.
Simplifying the value $\left( 4-2 \right)$. We know that the value of $4-2$ is $2$.
From the both the above values, we can write the value of $\left( 6+32 \right)\left( 4-2 \right)$ as
$\Rightarrow \left( 6+32 \right)\left( 4-2 \right)=38\times 2$
We have the value $38\times 2$ as $76$. From this value the above equation is modified as
$\Rightarrow \left( 6+32 \right)\left( 4-2 \right)=76$

Hence the simplified value of the given value $\left( 6+32 \right)\left( 4-2 \right)$ is $76$.

Note: In this problem we have only the brackets operation but they have mentioned to use the order of operation in the problem statement to confuse. But there is no confusion that the operations which are inside the bracket are not taken into count since in the brackets we have only one operation. If there are more than one operation, then we must consider them also.