How do you simplify $\dfrac{{\sin \theta }}{{1 + \cos \theta }} + \dfrac{{1 + \cos \theta }}{{\sin \theta }}$?
Answer
596.7k+ views
Hint: In this question we will try to take the Lowest common multiple to get a common denominator and then we will use the trigonometric identities to simplify the equation and get the final answer.
Complete step-by-step solution:
We have the equation:
$ \Rightarrow \dfrac{{\sin \theta }}{{1 + \cos \theta }} + \dfrac{{1 + \cos \theta }}{{\sin \theta }}$
Now since it is in the form of addition of two fractions, we will find the L.C.M as:
$ \Rightarrow \dfrac{{\sin \theta \times (\sin \theta )}}{{1 + \cos \theta \times (\sin \theta )}} + \dfrac{{(1 + \cos \theta ) \times (1 + \cos \theta )}}{{\sin \theta \times (1 + \cos \theta )}}$
Now since the denominator is same in both the fractions and since they are addition, we can write the equation as:
$ \Rightarrow \dfrac{{\sin \theta \times (\sin \theta ) + (1 + \cos \theta ) \times (1 + \cos \theta )}}{{(1 + \cos \theta ) \times \sin \theta }}$
On simplifying the numerator, we get:
$ \Rightarrow \dfrac{{{{\sin }^2}\theta + 1 + 2\cos \theta + {{\cos }^2}\theta }}{{(1 + \cos \theta ) \times \sin \theta }}$
Now since we know that ${\cos ^2}\theta + {\sin ^2}\theta = 1$ the numerator can be simplified and written as:
$ \Rightarrow \dfrac{{1 + 1 + 2\cos \theta }}{{(1 + \cos \theta ) \times \sin \theta }}$
On simplifying we get:
$ \Rightarrow \dfrac{{2 + 2\cos \theta }}{{(1 + \cos \theta ) \times \sin \theta }}$
Now since the number $2$ is common in both the terms in the numerator, we can take it out and write it as:
$ \Rightarrow \dfrac{{2(1 + \cos \theta )}}{{(1 + \cos \theta ) \times \sin \theta }}$
Now since $1 + \cos \theta $ is common in both the numerator and denominator we can cancel and write it as:
$ \Rightarrow \dfrac{2}{{\sin \theta }}$
Now we know that $\dfrac{1}{{\sin \theta }} = \csc \theta $
Therefore, on substituting we get:
$ \Rightarrow 2\csc \theta $, which is the final answer.
Note: It is to be remembered that to add two or more fractions, the denominator of both them should be the same, if the denominator is not the same, the lowest common multiple known as L.C.M should be taken.
The various trigonometric identities and formulae should be remembered while doing these types of sums. The various Pythagorean identities should also be remembered while doing these types of questions.
To simplify any given equation, it is good practice to convert all the identities into $\sin $ and $\cos $ for simplifying.
If there is nothing to simplify, then only you should use the double angle formulas to expand the given equation.
Complete step-by-step solution:
We have the equation:
$ \Rightarrow \dfrac{{\sin \theta }}{{1 + \cos \theta }} + \dfrac{{1 + \cos \theta }}{{\sin \theta }}$
Now since it is in the form of addition of two fractions, we will find the L.C.M as:
$ \Rightarrow \dfrac{{\sin \theta \times (\sin \theta )}}{{1 + \cos \theta \times (\sin \theta )}} + \dfrac{{(1 + \cos \theta ) \times (1 + \cos \theta )}}{{\sin \theta \times (1 + \cos \theta )}}$
Now since the denominator is same in both the fractions and since they are addition, we can write the equation as:
$ \Rightarrow \dfrac{{\sin \theta \times (\sin \theta ) + (1 + \cos \theta ) \times (1 + \cos \theta )}}{{(1 + \cos \theta ) \times \sin \theta }}$
On simplifying the numerator, we get:
$ \Rightarrow \dfrac{{{{\sin }^2}\theta + 1 + 2\cos \theta + {{\cos }^2}\theta }}{{(1 + \cos \theta ) \times \sin \theta }}$
Now since we know that ${\cos ^2}\theta + {\sin ^2}\theta = 1$ the numerator can be simplified and written as:
$ \Rightarrow \dfrac{{1 + 1 + 2\cos \theta }}{{(1 + \cos \theta ) \times \sin \theta }}$
On simplifying we get:
$ \Rightarrow \dfrac{{2 + 2\cos \theta }}{{(1 + \cos \theta ) \times \sin \theta }}$
Now since the number $2$ is common in both the terms in the numerator, we can take it out and write it as:
$ \Rightarrow \dfrac{{2(1 + \cos \theta )}}{{(1 + \cos \theta ) \times \sin \theta }}$
Now since $1 + \cos \theta $ is common in both the numerator and denominator we can cancel and write it as:
$ \Rightarrow \dfrac{2}{{\sin \theta }}$
Now we know that $\dfrac{1}{{\sin \theta }} = \csc \theta $
Therefore, on substituting we get:
$ \Rightarrow 2\csc \theta $, which is the final answer.
Note: It is to be remembered that to add two or more fractions, the denominator of both them should be the same, if the denominator is not the same, the lowest common multiple known as L.C.M should be taken.
The various trigonometric identities and formulae should be remembered while doing these types of sums. The various Pythagorean identities should also be remembered while doing these types of questions.
To simplify any given equation, it is good practice to convert all the identities into $\sin $ and $\cos $ for simplifying.
If there is nothing to simplify, then only you should use the double angle formulas to expand the given equation.
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