Question

How do you simplify $\dfrac{{{{\sin }^2}t + {{\cos }^2}t}}{{{{\cos }^2}t}}$?

Answer 1

Hint: This question is related to the trigonometry, and we have to simplify the expression and this can be done by using trigonometric identities, such as , ${\sin ^2}x + {\cos ^2}x = 1$ and $\cos x = \dfrac{1}{{\sec x}}$, and then further simplification of the expression we will get the required result.

Complete step by step answer:
Given trigonometric expression is $\dfrac{{{{\sin }^2}t + {{\cos }^2}t}}{{{{\cos }^2}t}}$,
We know that ${\sin ^2}x + {\cos ^2}x = 1$, Here $x = t$, by substituting the value we get,
$ \Rightarrow {\sin ^2}t + {\cos ^2}t = 1$,
Now by substituting the trigonometric identity in the given expression, we get,
$ \Rightarrow \dfrac{{{{\sin }^2}t + {{\cos }^2}t}}{{{{\cos }^2}t}} = \dfrac{1}{{{{\cos }^2}t}}$,
Now simplifying, we get,
$ \Rightarrow \dfrac{{{{\sin }^2}t + {{\cos }^2}t}}{{{{\cos }^2}t}} = {\left( {\dfrac{1}{{\cos t}}} \right)^2}$,
And by using the trigonometric identity which is given by,
$ \Rightarrow \dfrac{1}{{\cos x}} = \sec x$,
Then by substituting the identity in the above then the given trigonometric expression becomes,
$ \Rightarrow \dfrac{{{{\sin }^2}t + {{\cos }^2}t}}{{{{\cos }^2}t}} = {\left( {\sec t} \right)^2}$,
Now further simplifying we get,
$ \Rightarrow \dfrac{{{{\sin }^2}t + {{\cos }^2}t}}{{{{\cos }^2}t}} = {\sec ^2}t$,
From the above simplification we can say that $\dfrac{{{{\sin }^2}t + {{\cos }^2}t}}{{{{\cos }^2}t}} = {\sec ^2}t$,

So, simplified form of the given expression will be ${\sec ^2}t$.

Note: An identity is an equation that always holds true. A trigonometric identity is an identity that contains trigonometric functions and holds true for all right-angled triangles. They are useful when solving questions with trigonometric functions and expressions. There are six trigonometric ratios, sine, cosine, tangent, cosecant, secant and cotangent. These six trigonometric ratios are abbreviated as sin, cos, tan, csc, sec, cot. These are referred to as ratios since they can be expressed in terms of the sides of a right-angled triangle for a specific angle θ. There are many trigonometric identities, here are some useful identities:
1. ${\sin ^2}x = 1 - {\cos ^2}x$,
2. ${\cos ^2}x + {\sin ^2}x = 1$,
3. ${\sec ^2}x - {\tan ^2}x = 1$,
4. ${\csc ^2}x = 1 + {\cot ^2}x$,
5. ${\cos ^2}x - {\sin ^2}x = 1 - 2{\sin ^2}x$,
6. ${\cos ^2}x - {\sin ^2}x = 2{\cos ^2}x - 1$,
7. $\sin 2x = 2\sin x\cos x$,
8. $2{\cos ^2}x = 1 + \cos 2x$,
9. $\tan 2x = \dfrac{{2\tan x}}{{1 - {{\tan }^2}x}}$.