Simplify and solve the following linear equation:
$0.25\left( {4f - 3} \right) = 0.05\left( {10f - 9} \right)$
Answer
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Hint: Remove the brackets and solve for the unknown.
The given equation is $0.25\left( {4f - 3} \right) = 0.05\left( {10f - 9} \right)$
First let us expand the brackets.
Expanding the brackets, we get
$\begin{gathered}
0.25\left( {4f - 3} \right) = 0.05\left( {10f - 9} \right) \\
0.25\left( {4f} \right) - 3\left( {0.25} \right) = 0.05\left( {10f} \right) - 9\left( {0.05} \right)
\\
f - 0.75 = 0.5f - 0.45 \\
\end{gathered} $
Rearranging the equation by combining the like terms and the constants, we get
$\begin{gathered}
f - 0.5f = 0.75 - 0.45 \\
0.5f = 0.30 \\
\end{gathered} $
Multiplying both sides by 10 to remove the decimals for easier calculation,
$\begin{gathered}
5f = 3 \\
f = \dfrac{3}{5} \\
\end{gathered} $
Since the equation is given in decimal, we will find the decimal value too for$f$.
Hence,$f = \dfrac{3}{5} = 0.6$
Note: To check if the answer is correct, substitute the value of back into the given equation
and check if you get LHS=RHS. The process of simplifying a linear is just arranging all the like
terms to one side and the constants to the other side and solving for the unknown value.
The given equation is $0.25\left( {4f - 3} \right) = 0.05\left( {10f - 9} \right)$
First let us expand the brackets.
Expanding the brackets, we get
$\begin{gathered}
0.25\left( {4f - 3} \right) = 0.05\left( {10f - 9} \right) \\
0.25\left( {4f} \right) - 3\left( {0.25} \right) = 0.05\left( {10f} \right) - 9\left( {0.05} \right)
\\
f - 0.75 = 0.5f - 0.45 \\
\end{gathered} $
Rearranging the equation by combining the like terms and the constants, we get
$\begin{gathered}
f - 0.5f = 0.75 - 0.45 \\
0.5f = 0.30 \\
\end{gathered} $
Multiplying both sides by 10 to remove the decimals for easier calculation,
$\begin{gathered}
5f = 3 \\
f = \dfrac{3}{5} \\
\end{gathered} $
Since the equation is given in decimal, we will find the decimal value too for$f$.
Hence,$f = \dfrac{3}{5} = 0.6$
Note: To check if the answer is correct, substitute the value of back into the given equation
and check if you get LHS=RHS. The process of simplifying a linear is just arranging all the like
terms to one side and the constants to the other side and solving for the unknown value.
Last updated date: 25th Sep 2023
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