
Simplify and express in exponential form
\[\;\dfrac{{{{({9^3})}^2} \times {7^4}}}{{{3^8} \times 21}}\]
Answer
568.8k+ views
Hint: To simplify the given expression try to break in small power rather than directly calculating the value of the given expression, we basically use laws of exponents to solve such problems.
Complete step-by-step answer:
The given expression is
\[\;\dfrac{{{{({9^3})}^2} \times {7^4}}}{{{3^8} \times 21}}\]
In numerator multiply the powers of 9 and in denominator break 21 as \[3 \times 7\]
We get,
\[ = \dfrac{{{{\left( 9 \right)}^{3 \times 2}} \times {7^4}}}{{{3^8} \times 7 \times 3}}\]
In denominator add all the powers of 3
We get,
\[ = \dfrac{{{9^6} \times {7^4}}}{{{3^9} \times 7}}\]
Bring 7 from denominator to numerator and add the power
We get,
\[ = \dfrac{{{9^6} \times {7^{4 - 1}}}}{{{3^9}}} = \dfrac{{{9^6} \times {7^3}}}{{{3^9}}}\]
Write 9 as 32 then add their powers
We get,
\[\; = \dfrac{{{{({3^2})}^6} \times {7^3}}}{{{3^9}}} = \dfrac{{{3^{12}} \times {7^3}}}{{{3^9}}}\]
Bring 39 to the numerator and add their power
We get,
\[ = {3^{12 - 9}} \times {7^3} = {3^3} \times {7^3}\]
Multiply 3 and 7 as the power is same
\[{\left( {21} \right)^3}\]
We get 213 so multiply 21 three times
We get,
\[ = 21 \times 21 \times 21\]
Hence the simplified form is
\[ = 9261\]
So, the correct answer is “9621”.
Note: When multiplying like bases, keep the base the same and add the exponents. When raising a base with a power to another power, keep the base the same and multiply the exponents. When dividing like bases, keep the base the same and subtract the denominator exponent from the numerator exponent.
Complete step-by-step answer:
The given expression is
\[\;\dfrac{{{{({9^3})}^2} \times {7^4}}}{{{3^8} \times 21}}\]
In numerator multiply the powers of 9 and in denominator break 21 as \[3 \times 7\]
We get,
\[ = \dfrac{{{{\left( 9 \right)}^{3 \times 2}} \times {7^4}}}{{{3^8} \times 7 \times 3}}\]
In denominator add all the powers of 3
We get,
\[ = \dfrac{{{9^6} \times {7^4}}}{{{3^9} \times 7}}\]
Bring 7 from denominator to numerator and add the power
We get,
\[ = \dfrac{{{9^6} \times {7^{4 - 1}}}}{{{3^9}}} = \dfrac{{{9^6} \times {7^3}}}{{{3^9}}}\]
Write 9 as 32 then add their powers
We get,
\[\; = \dfrac{{{{({3^2})}^6} \times {7^3}}}{{{3^9}}} = \dfrac{{{3^{12}} \times {7^3}}}{{{3^9}}}\]
Bring 39 to the numerator and add their power
We get,
\[ = {3^{12 - 9}} \times {7^3} = {3^3} \times {7^3}\]
Multiply 3 and 7 as the power is same
\[{\left( {21} \right)^3}\]
We get 213 so multiply 21 three times
We get,
\[ = 21 \times 21 \times 21\]
Hence the simplified form is
\[ = 9261\]
So, the correct answer is “9621”.
Note: When multiplying like bases, keep the base the same and add the exponents. When raising a base with a power to another power, keep the base the same and multiply the exponents. When dividing like bases, keep the base the same and subtract the denominator exponent from the numerator exponent.
Recently Updated Pages
Master Class 5 Science: Engaging Questions & Answers for Success

Class 5 Question and Answer - Your Ultimate Solutions Guide

Master Class 5 English: Engaging Questions & Answers for Success

Master Class 5 Maths: Engaging Questions & Answers for Success

Master Class 5 Social Science: Engaging Questions & Answers for Success

Master Class 4 English: Engaging Questions & Answers for Success

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Full form of STD, ISD and PCO

Convert 40circ C to Fahrenheit A 104circ F B 107circ class 8 maths CBSE

Advantages and disadvantages of science

Right to vote is a AFundamental Right BFundamental class 8 social science CBSE


