
How do you simplify ${9^{ - \dfrac{1}{2}}}$ leaving only positive exponent?
Answer
545.7k+ views
Hint: The power of half always means to take the square root of the number. Negative powers can be solved by interchanging certain aspects of base. Knowledge of fraction and their procedure to reciprocate them will be useful in this question. Reciprocation can be done by changing the sign of the exponent.
Complete step-by-step answer:
We are given the number $9$ to the negative power of $1/2$ . As we know the power of half that is $1/2$ means we have to take the square root of the base to which this power is raised. But we are hindered with a negative sign which is not a big huddle to remove. Any fraction let us say $\dfrac{a}{b}$ can be written opposite which means by exchanging numerator and denominator’s position. In this example ‘a’ will be replaced by ‘b’ and ‘b’ will be replaced by ‘a’. This change can only be done if we put a negative one exponent on the whole fraction after exchanging the numerator and denominator. So our assumed fraction will look like ${\left( {\dfrac{b}{a}} \right)^{ - 1}}$ .
So from this example, the reverse is also true. If we are given a base with a negative exponent, we can make the exponent positive by reversing the numerator and denominator of the base. Also if the base is not a fraction, then it can be reversed by putting $1$ on the numerator and the base on the denominator by making the exponent positive.
Now let us apply this on the expression we have which is ${9^{ - \dfrac{1}{2}}}$
${9^{ - \dfrac{1}{2}}} = \dfrac{1}{{{9^{\dfrac{1}{2}}}}}$
We know power of half means square root so,
$ \Rightarrow {9^{ - \dfrac{1}{2}}} = \dfrac{1}{{\sqrt 9 }}$
On evaluating,
$ \Rightarrow {9^{ - \dfrac{1}{2}}} = \dfrac{1}{3}$
So $\dfrac{1}{3}$ is our required answer.
Note: Be careful of the sign of the exponent while reciprocating the fraction. Since a positive exponent is thought to be of repeated multiplication by the base. In the same way a negative exponent can be thought of repeated division by the base. It is to be noted that polynomials cannot have negative exponents.
Complete step-by-step answer:
We are given the number $9$ to the negative power of $1/2$ . As we know the power of half that is $1/2$ means we have to take the square root of the base to which this power is raised. But we are hindered with a negative sign which is not a big huddle to remove. Any fraction let us say $\dfrac{a}{b}$ can be written opposite which means by exchanging numerator and denominator’s position. In this example ‘a’ will be replaced by ‘b’ and ‘b’ will be replaced by ‘a’. This change can only be done if we put a negative one exponent on the whole fraction after exchanging the numerator and denominator. So our assumed fraction will look like ${\left( {\dfrac{b}{a}} \right)^{ - 1}}$ .
So from this example, the reverse is also true. If we are given a base with a negative exponent, we can make the exponent positive by reversing the numerator and denominator of the base. Also if the base is not a fraction, then it can be reversed by putting $1$ on the numerator and the base on the denominator by making the exponent positive.
Now let us apply this on the expression we have which is ${9^{ - \dfrac{1}{2}}}$
${9^{ - \dfrac{1}{2}}} = \dfrac{1}{{{9^{\dfrac{1}{2}}}}}$
We know power of half means square root so,
$ \Rightarrow {9^{ - \dfrac{1}{2}}} = \dfrac{1}{{\sqrt 9 }}$
On evaluating,
$ \Rightarrow {9^{ - \dfrac{1}{2}}} = \dfrac{1}{3}$
So $\dfrac{1}{3}$ is our required answer.
Note: Be careful of the sign of the exponent while reciprocating the fraction. Since a positive exponent is thought to be of repeated multiplication by the base. In the same way a negative exponent can be thought of repeated division by the base. It is to be noted that polynomials cannot have negative exponents.
Recently Updated Pages
You are awaiting your class 10th results Meanwhile class 7 english CBSE

Master Class 7 Social Science: Engaging Questions & Answers for Success

Master Class 7 Science: Engaging Questions & Answers for Success

Class 7 Question and Answer - Your Ultimate Solutions Guide

Master Class 7 English: Engaging Questions & Answers for Success

Master Class 7 Maths: Engaging Questions & Answers for Success

Trending doubts
Convert 200 Million dollars in rupees class 7 maths CBSE

Full Form of IASDMIPSIFSIRSPOLICE class 7 social science CBSE

i What trees does Mr Wonka mention Which tree does class 7 english CBSE

What are the controls affecting the climate of Ind class 7 social science CBSE

What was the main occupation of early Aryans of rig class 7 social science CBSE

Write a letter to the editor of the national daily class 7 english CBSE


