
How do you simplify \[6\left\{ 13-2\left( 4+1 \right) \right\}\]?
Answer
443.7k+ views
Hint: In this problem, we have to simplify the given expression. We can first take the terms inside the brackets and add it, then we can multiply the added number to the number outside the bracket. Then we can subtract the terms inside the bracket, then we can again multiply the last term outside to get the simplified form. We can also use the BODMAS- which means Brackets of Division, Multiplication, Addition and Subtraction to solve these types of problems.
Complete step by step solution:
We know that the given expression to be simplified is,
\[6\left\{ 13-2\left( 4+1 \right) \right\}\]
We can use the BODMAS- which means Brackets of Division, Multiplication, Addition and Subtraction to solve these types of problems.
We can first take the terms inside the brackets and add it, we get
\[\Rightarrow 6\left\{ 13-2\left( 5 \right) \right\}\]
We can multiply the added number to the number outside the bracket, we get
\[\Rightarrow 6\left\{ 13-10 \right\}\].
We can subtract the terms inside the bracket, we get
\[\Rightarrow 6\left\{ 3 \right\}\]
we can again multiply the last term outside to get the simplified form, we get
\[\Rightarrow 18\]
Note: Students may get confused about how to solve these types of problems in a step by step way for this we have to know that BODMAS method, which means Brackets of Division, Multiplication, Addition and Subtraction to solve these types of problems. We should also know the multiplication tables to solve or simplify these types of problems.
Complete step by step solution:
We know that the given expression to be simplified is,
\[6\left\{ 13-2\left( 4+1 \right) \right\}\]
We can use the BODMAS- which means Brackets of Division, Multiplication, Addition and Subtraction to solve these types of problems.
We can first take the terms inside the brackets and add it, we get
\[\Rightarrow 6\left\{ 13-2\left( 5 \right) \right\}\]
We can multiply the added number to the number outside the bracket, we get
\[\Rightarrow 6\left\{ 13-10 \right\}\].
We can subtract the terms inside the bracket, we get
\[\Rightarrow 6\left\{ 3 \right\}\]
we can again multiply the last term outside to get the simplified form, we get
\[\Rightarrow 18\]
Note: Students may get confused about how to solve these types of problems in a step by step way for this we have to know that BODMAS method, which means Brackets of Division, Multiplication, Addition and Subtraction to solve these types of problems. We should also know the multiplication tables to solve or simplify these types of problems.
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