Simplification of $3\dfrac{1}{5} \times 10\dfrac{1}{2}$ gives us
${\text{A}}{\text{. }}\dfrac{{166}}{5}$
${\text{B}}{\text{. }}\dfrac{{167}}{5}$
${\text{C}}{\text{. }}\dfrac{{168}}{5}$
${\text{D}}{\text{. }}\dfrac{{161}}{5}$
Answer
635.7k+ views
Hint: Here mixed fractions are given in the problem, so first we convert these mixed fractions into proper fractions like $3\dfrac{1}{5} = \dfrac{{16}}{5}$ and $10\dfrac{1}{2} = \dfrac{{21}}{2}$, after converting into proper fractions, perform the multiplication to find the answer.
Complete step-by-step solution -
We have been asked in the question to find the value of the expression-
$3\dfrac{1}{5} \times 10\dfrac{1}{2} \to (1)$.
Using the hint, we can write –
$3\dfrac{1}{5} = \dfrac{{16}}{5}$ and $10\dfrac{1}{2} = \dfrac{{21}}{2}$.
Putting these values in equation (1), we get-
$3\dfrac{1}{5} \times 10\dfrac{1}{2} = \dfrac{{16}}{5} \times \dfrac{{21}}{2} = \dfrac{{168}}{5}$
Hence, the answer is option ${\text{C}}{\text{. }}\dfrac{{168}}{5}$.
Note: Whenever such types of questions appear, try to simplify the given expression in the simplest form, as mentioned in the solution. We have found the whole fraction value of both the terms and then put the values in the expression to find the answer.
Complete step-by-step solution -
We have been asked in the question to find the value of the expression-
$3\dfrac{1}{5} \times 10\dfrac{1}{2} \to (1)$.
Using the hint, we can write –
$3\dfrac{1}{5} = \dfrac{{16}}{5}$ and $10\dfrac{1}{2} = \dfrac{{21}}{2}$.
Putting these values in equation (1), we get-
$3\dfrac{1}{5} \times 10\dfrac{1}{2} = \dfrac{{16}}{5} \times \dfrac{{21}}{2} = \dfrac{{168}}{5}$
Hence, the answer is option ${\text{C}}{\text{. }}\dfrac{{168}}{5}$.
Note: Whenever such types of questions appear, try to simplify the given expression in the simplest form, as mentioned in the solution. We have found the whole fraction value of both the terms and then put the values in the expression to find the answer.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 9 Social Science: Engaging Questions & Answers for Success

Master Class 9 Science: Engaging Questions & Answers for Success

Master Class 9 Maths: Engaging Questions & Answers for Success

Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Class 9 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
Find the sum of series 1 + 2 + 3 + 4 + 5 + + 100 class 9 maths CBSE

What is the Full Form of ISI and RAW

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Difference Between Plant Cell and Animal Cell

Who is eligible for RTE class 9 social science CBSE

What is pollution? How many types of pollution? Define it


