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How many sigma and pi bonds are there in the given molecule?
\[H - C \equiv C - C{H_2} - CH = C{H_2}\]
A. There are 3 pi bonds and 10 sigma bonds
B. There are 12 sigma bonds and 4 pi bonds
C. There are 2 pi bonds and 4 sigma bonds
D. There are 8 sigma bonds and 2 pi bonds

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Answer
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Hint: Sigma bonds are included in single bonds as well in the non-single bonds. Pi bonds are included in the double or triple bond.

Complete step by step answer:
We know that single bond \[\left( {{\text{C}} - {\text{H}}} \right)\] includes one sigma bond and double\[\left( {{\text{C}} = {\text{H}}} \right)\] and triple \[\left( {{\text{C}} \equiv {\text{H}}} \right)\] bonds consists of one sigma bond and the remaining bonds are pi bonds. Let us number the sigma bonds and the pi bonds in the given compound.
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The blue numbers indicate pi bonds and the red numbers indicates sigma bonds.
Therefore, in the compound, \[H - C \equiv C - C{H_2} - CH = C{H_2}\] there exist 10 sigma bonds and 3 pi bonds.
So, we can conclude that out of the given four options, A is the correct option. B, C and D are incorrect options.

Additional information:
A sigma bond and a pi bond are formed by the overlapping of atomic orbitals. The end to end atomic orbital overlapping results in the formation of a sigma bond and the side to side overlap of the atomic orbitals generates the pi bond. We can show the orbital overlap in both the bonds in the following way.
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Note:Sigma bonds are stronger than pi bonds. Pi bonds are considered to be weak bonds. A bond is considered to be a strong bond if they include both the pi bond and the sigma bond together.