Question

Select the correct IUPAC name for ${{[PtC{{l}_{4}}]}^{2-}}$
a.) Tetrachloride Platinum (II) ion
b.) Tetrachloride Platinum (2-) ion
c.) Tetrachloridoplatinante (II) ion
d.) Tetrachloroplatinate (2-) ion

Answer 1

Hint: To write the IUPAC nomenclature we have to understand the compound structure and the functional group attached to it. For the IUPAC naming of compounds there are certain rules to be followed and also we should calculate the oxidation number on the central metal ion.

Complete Solution :
First calculate the oxidation state of the central metal atom which is Pt in ${{[PtC{{l}_{4}}]}^{2-}}$
Oxidation state of Cl in the given compound = -1
Oxidation state of the central metal atom ion Pt =
\[\begin{align}
 & x + 4(-1) = -2 \\
 & x - 4 = -2 \\
 & x = +2 \\
\end{align}\]
Hence, the oxidation state of the central metal ion is +2. The number of chlorine atoms here is 4 so the name will be tetrachloride.
- The oxidation state while writing the IUPAC nomenclature will be written in roman numbers inside brackets. If more than one atom is present, suffixes like di, tri, tetra are used. If the cation is present outside the bracket then ate is added to the name of the central metal ion.
The correct IUPAC name for ${{[PtC{{l}_{4}}]}^{2-}}$ i.e. Tetrachloridoplatinante (II) ion.
So, the correct answer is “Option C”.

Note: While writing the IUPAC nomenclature the substituents present in the given compound should be arranged in alphabetical order and if the same substituent occurs more than one then the prefix like di, tri, tetra etc. are used. It is important to put a comma between two numbers and a dash between a number and the name of the substituent. While arranging the substituents in alphabetical order we should ignore the prefix like di, tri, and tetra and arrange on the basis of the first letter of the substituent name.