Select the compound in which the chlorine shows oxidation state \[+7\].
A \[HCl{{O}_{4}}\]
B \[HCl{{O}_{3}}\]
C \[HCl{{O}_{2}}\]
D \[HClO\]
Answer
621.9k+ views
Hint: The oxidation state, sometimes referred to as oxidation number, describes the degree of oxidation (loss of electrons) of an atom in a chemical compound. Conceptually, the oxidation state, which may be positive, negative, or zero, is the hypothetical charge that an atom would have if all bonds to atoms of different elements were 100% ionic, with no covalent component. This is never exactly true for real bonds.
Complete step by step answer:
Here, we have four compounds of chlorine. So, we have to find the oxidation state of chlorine in each compound to find the answer that is in which compound chlorine shows oxidation state is \[+7\]. Let us calculate the oxidation state of the chlorine in each compound;
We have known that the oxidation state of hydrogen and oxygen is fixed, i.e. \[+1\] and \[-2\] respectively. Let \[x\] be the oxidation state of chlorine in each compounds;
In \[HCl{{O}_{4}}\], we have one chlorine atom, one hydrogen atom and four oxygen atom. So, we can write as
\[\Rightarrow 1+x+4(-2)=0\]
\[\Rightarrow x=+7\]
In,\[HCl{{O}_{3}}\], we have one chlorine atom, one hydrogen atom and three oxygen atoms. So, we can write as
\[\Rightarrow 1+x+3(-2)=0\]
\[\Rightarrow x=+5\]
In, \[HCl{{O}_{2}}\] we have one chlorine atom, one hydrogen atom, and two oxygen atoms. So, we can write as
\[\Rightarrow 1+x+2(-2)=0\]
\[\Rightarrow x=+3\]
In, \[HClO\] we have one chlorine atom, one hydrogen atom and one three oxygen atoms. So, we can write as
\[\Rightarrow 1+x+1(-2)=0\]
\[\Rightarrow x=+1\]
So, chlorine shows \[+7\]\[HCl{{O}_{4}}\]in only. Hence, the correct answer is option A.
Note: Like hydrogen and oxygen there are some more elements whose oxidation states are fixed in chemical compounds. Group 1 and group 2 metals in compounds have oxidation states is = +1 and +2, respectively. Also, the oxidation state of an element in free form is equal to zero.
Complete step by step answer:
Here, we have four compounds of chlorine. So, we have to find the oxidation state of chlorine in each compound to find the answer that is in which compound chlorine shows oxidation state is \[+7\]. Let us calculate the oxidation state of the chlorine in each compound;
We have known that the oxidation state of hydrogen and oxygen is fixed, i.e. \[+1\] and \[-2\] respectively. Let \[x\] be the oxidation state of chlorine in each compounds;
In \[HCl{{O}_{4}}\], we have one chlorine atom, one hydrogen atom and four oxygen atom. So, we can write as
\[\Rightarrow 1+x+4(-2)=0\]
\[\Rightarrow x=+7\]
In,\[HCl{{O}_{3}}\], we have one chlorine atom, one hydrogen atom and three oxygen atoms. So, we can write as
\[\Rightarrow 1+x+3(-2)=0\]
\[\Rightarrow x=+5\]
In, \[HCl{{O}_{2}}\] we have one chlorine atom, one hydrogen atom, and two oxygen atoms. So, we can write as
\[\Rightarrow 1+x+2(-2)=0\]
\[\Rightarrow x=+3\]
In, \[HClO\] we have one chlorine atom, one hydrogen atom and one three oxygen atoms. So, we can write as
\[\Rightarrow 1+x+1(-2)=0\]
\[\Rightarrow x=+1\]
So, chlorine shows \[+7\]\[HCl{{O}_{4}}\]in only. Hence, the correct answer is option A.
Note: Like hydrogen and oxygen there are some more elements whose oxidation states are fixed in chemical compounds. Group 1 and group 2 metals in compounds have oxidation states is = +1 and +2, respectively. Also, the oxidation state of an element in free form is equal to zero.
Recently Updated Pages
The given figure shows two endocrine glands marked class 11 biology NEET_UG

Match columnI with columnII and select the correct class 11 biology NEET

Match column I with column II and select the correct class 11 biology NEET_UG

Which floral family has left 9 right + 1 arrangement class 11 biology NEET_UG

Which is not a variety of sheep A Lohi B Beetal C Nellore class 11 biology NEET_UG

Match column I with column II and select the correct class 11 biology NEET_UG

Trending doubts
Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

10 examples of law on inertia in our daily life

