
How many seconds will it take for a satellite to travel 450km at the rate of 120m/s?
Answer
542.7k+ views
Hint: The above problem is based on the simple formula of time is equal to distance upon speed.
The formula of the time is given as:
$Time = \dfrac{\text{Distance}}{\text{speed}}$
No matter the satellite is given or any other object the formula for calculating the time will remain the same.
Using the above mentioned formula we will solve the given problem.
Complete step by step answer:
Let's discuss the satellites a few points before going into the calculations.
Satellite is an object that has been intentionally placed into orbit. These objects are called artificial satellites to distinguish them from natural satellites such as Earth's moon. The Moon is the Earth's natural satellite. For various functions such as television communication, radio communication and other applications various countries keep on launching their individual satellites for their use. World's first satellite was launched by Soviet Union which was named as SPUTNIK 1.
Now, we will perform the calculation part of the problem.
Distance given to us is 450Km, in meters it is written as $450 \times {10^3}$ (1Km = 1000 m).We will calculate the answer in seconds therefore we will calculate the distance in meters.
Speed given 120 m/s.
Therefore, time can be calculated as;
$Time = \dfrac{\text{Distance}}{\text{speed}}$
$ \Rightarrow T = \dfrac{{450 \times 1000}}{{120}}$ (T is the time)
$ \Rightarrow T = 3750s$
Satellites will take 3750 seconds to move.
Note: Satellites have many applications such as maps of planetary surfaces, and also take pictures of planets for which the satellite is designed to study. As we have seen there are many recent studies and discoveries have been done for Mars and Moon. India had launched Chandrayan-1 and 2 missions in order to study about the Moon.
The formula of the time is given as:
$Time = \dfrac{\text{Distance}}{\text{speed}}$
No matter the satellite is given or any other object the formula for calculating the time will remain the same.
Using the above mentioned formula we will solve the given problem.
Complete step by step answer:
Let's discuss the satellites a few points before going into the calculations.
Satellite is an object that has been intentionally placed into orbit. These objects are called artificial satellites to distinguish them from natural satellites such as Earth's moon. The Moon is the Earth's natural satellite. For various functions such as television communication, radio communication and other applications various countries keep on launching their individual satellites for their use. World's first satellite was launched by Soviet Union which was named as SPUTNIK 1.
Now, we will perform the calculation part of the problem.
Distance given to us is 450Km, in meters it is written as $450 \times {10^3}$ (1Km = 1000 m).We will calculate the answer in seconds therefore we will calculate the distance in meters.
Speed given 120 m/s.
Therefore, time can be calculated as;
$Time = \dfrac{\text{Distance}}{\text{speed}}$
$ \Rightarrow T = \dfrac{{450 \times 1000}}{{120}}$ (T is the time)
$ \Rightarrow T = 3750s$
Satellites will take 3750 seconds to move.
Note: Satellites have many applications such as maps of planetary surfaces, and also take pictures of planets for which the satellite is designed to study. As we have seen there are many recent studies and discoveries have been done for Mars and Moon. India had launched Chandrayan-1 and 2 missions in order to study about the Moon.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

