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Saurabh takes 15 minutes to reach school from his house and Sachin takes one hour to reach school from his house. Find the ratio of the time taken by Saurabh to the time taken by Sachin.

Answer
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Hint: Convert the time taken by Sachin to reach school into minutes by using the fact that ‘x’ hours is equal to $x\times 60$ minutes. Divide the time taken by both of them in minutes and simplify the fraction by taking out common terms from numerator and denominator to calculate the ratio of time taken by both of them to reach the school.

Complete step-by-step answer:
We know that Saurabh takes 15 minutes to reach school and Sachin takes 1 hour to reach school. We have to calculate the ratio of time taken by both of them to reach school.
We will convert the time taken by Sachin to reach school into minutes. We know that ‘x’ hours is equal to $x\times 60$ minutes.
Substituting $x=1$ in the above expression, we have $1hr=60\min $.
We will now calculate the ratio of time taken by both of them. To do so, we will divide the time taken by them in minutes. Thus, the ratio is $\dfrac{15}{60}$.
We will now simplify this fraction. Thus, we have $\dfrac{15}{60}=\dfrac{15}{15\times 4}=\dfrac{1}{4}$.
Hence, the ratio of time taken by them to reach school is $\dfrac{1}{4}=1:4$.

Note: One must keep in mind that the ratio of two numbers is the value obtained by dividing one number by other. To calculate the ratio of any two quantities, both the quantities must have the same units of measurement.