Question

Salle plants $4$ saplings in a row in her garden. The distance between two adjacent saplings is $\dfrac{3}{4}\,m$. Find the distance between the first and the last saplings.

Answer 1

Hint: In order to find the distance between the first and last samplings, we would simply add the distance between two adjacent distance three times, one for the first two saplings, second for first and third and then from first to last.

Complete step by step answer:
We are given that there are four samplings in a row in Salle’s garden. And, the distance between two adjacent saplings is $\dfrac{3}{4}m$.We can reach the fourth saplings, by adding the distance between the adjacent rows like: distance from first to second$ + $ distance from second to third $ + $ distance from third to fourth.

The first two saplings have a distance of $\dfrac{3}{4}m$. So, adding this distance to the distance of the first two saplings, so that we reach the third saplings. So, the distance between the first and the third sapling is:
first to second$ + $second to third $ = \dfrac{3}{4}m + \dfrac{3}{4}m = \dfrac{6}{4}m$.
Adding again the distance $\dfrac{3}{4}m$, to the distance obtained from first sapling to third, so that we can reach the fourth saplings. So, the distance between the first and fourth sapling is:
$\dfrac{6}{4}m + \dfrac{3}{4}m = \dfrac{9}{4}m$

Therefore, the distance between the first and the last saplings is $\dfrac{9}{4}\,m$.

Note:We can also find the distance from first to fourth directly by multiplying $3$ to $\dfrac{3}{4}m$. Because there are four saplings, and there are three distances one from first to second, next from second to third and third to fourth. Since, there are three adjacent saplings, having equal distances. The distance between two adjacent saplings is $\dfrac{3}{4}\,m$. So, for all the four, the distance from first to fourth becomes $\dfrac{3}{4} \times 3\,m = \dfrac{9}{4}\,m$.