Question

Riaz takes $20\,\min $to travel to his school with a speed of $3\,m/s\,.$ How far is the school?

Answer 1

Hint: Before solving the question let us get some idea about the speed. Speed is a scalar variable that refers to "how fast an object is travelling," or the rate at which an object travels a given distance. An object with zero speed is one that does not move at all.

Complete step by step answer:
The rate at which an object moves from one location to another is called speed. It is calculated by dividing the \text{Distance} travelled by the time. In the triangle, distance is across time, hence speed equals \text{Distance} divided by time. Speed is beside time when calculating \text{Distance}, thus \text{Distance} equals speed multiplied by time.We can say that,
$Speed = \dfrac{{\text{Distance}}}{text{Time}}$
$\text{Distance} = \text{Speed} \times \text{Time}$

Given: So, given in the question that, Riaz takes $20\,\min $travels to his school and his speed is $3\,m/s$. Now, let's convert $20\,\min $ into seconds. As we know,
$1\,\min = \,60\,\sec $
$\Rightarrow 20\,\min \, \times \,60\, = 1200\,\sec $
Now, as we saw above that
$\text{Distance} = Speed \times Time$
$\Rightarrow \text{Distance} = \,3 \times 1200$
$\Rightarrow \text{Distance} = 3600\,m$
By converting meters in kilometers.
$\therefore \text{Distance} = \dfrac{{3600}}{{1000}} = 3.6\,km$

Hence, school is 3.6 km far away.

Additional Information: The term "distance" refers to "how much ground an object has covered" during its travel. The overall change in location of an object is defined by displacement, which is a vector quantity that describes "how far an object is out of place."

Note: The term "motion" refers to a shift in position. Every movement is in relation to a fixed point or object. The change in location over time is measured as speed. The rate of movement in a particular direction is called velocity. Acceleration is defined as an increase in speed or velocity over time