Question

Rhombic sulphur has the following structure
(A) Open chain
(B) Tetrahedral
(C) Puckered 6 – membered ring
(D) Puckered 8 – membered ring

Answer 1

Hint: Sulphur in the form of rhombic sulphur is a crystalline allotropic form of the material. Sulphur in this form is the most stable. On standing, all other forms of sulphur ultimately return to rhombic form.

Complete answer:
-Open chain:
An open chain is a chain of atoms that is not joined at the ends and is thus reflected in its structural formula.
-Tetrahedral:
This molecule is made up of 4 sp3 hybrid orbitals that are evenly spaced and have bond angles of 109.5°. The orbitals have a tetrahedral form. Since each orbital has an atom at the centre, the molecule's form is tetrahedral.
-Puckered 6 – membered ring
The puckered 6-membered ring is a stable ring structure found in cycloalkanes (cyclohexane), and it is now referred to as an aromatic device.
-Puckered 8 – membered ring
Both naturally occurring elements would have an elemental form. Since it is the most stable structure and formula, this is the one the element would use the most.
In its elemental form, sulphur has an octatomic structure. This implies there are eight sulphur atoms arranged in a cyclic pattern.
Rhombic sulphur has a definite molecular structure. The S8 molecule is an 8-atom puckered ring with a 2.12A S-S distance.

Thus, option (D) is the answer.

Note:
Powdered sulphur is dissolved in carbon disulphide at room temperature to make rhombic sulphur. After that, the mixture is filtered. The filtrate is then stored in a small beaker with filter paper on top. The carbon disulphide would slowly evaporate, leaving massive octahedral rhombic sulphur (or –sulphur) crystals behind.