
How do you rewrite the expression $ \dfrac{{{x^2}}}{{{y^3}}} $ without fractions?
Answer
528k+ views
Hint: We have to eliminate the fraction in this question. We will do this by getting the reciprocal of the denominator of this given fraction. Since the reciprocal will convert the whole fraction to one type which in this case is the numerator and we will thus have to eliminate the fractions from the given question. We have to find the reciprocal of the denominator but since our denominator contains an index (also called exponent) we will have to use the law of indices in doing the reciprocal. The identity which we will have to use is the identity that will change the positive index to the negative index and also do the reciprocal. The identity is given below,
$ {a^y} = \dfrac{1}{{{a^{ - y}}}} $
This we will apply on the denominator and get our answer in the numerator.
Complete step by step solution:
The given question asks us to convert the given number into a number without a fraction. We will use the law for taking reciprocal of positive index and changing it into a negative index. The formula we will use is
$ {a^y} = \dfrac{1}{{{a^{ - y}}}} $
Our question will become,
$ \dfrac{{{x^2}}}{{{y^3}}} = {x^2} \times {y^{ - 3}} $
We will then elegantly write our answer as,
$ {x^2}{y^{ - 3}} $
Which is the required answer.
So, the correct answer is “ $ {x^2}{y^{ - 3}} $ ”.
Note: We should always remember that whenever we have a positive power we can easily convert it into negative power but it will also render the reciprocal of the number instead of the original number this specific law of exponent is written in the below written formula,
$ {a^y} = \dfrac{1}{{{a^{ - y}}}} $
$ {a^y} = \dfrac{1}{{{a^{ - y}}}} $
This we will apply on the denominator and get our answer in the numerator.
Complete step by step solution:
The given question asks us to convert the given number into a number without a fraction. We will use the law for taking reciprocal of positive index and changing it into a negative index. The formula we will use is
$ {a^y} = \dfrac{1}{{{a^{ - y}}}} $
Our question will become,
$ \dfrac{{{x^2}}}{{{y^3}}} = {x^2} \times {y^{ - 3}} $
We will then elegantly write our answer as,
$ {x^2}{y^{ - 3}} $
Which is the required answer.
So, the correct answer is “ $ {x^2}{y^{ - 3}} $ ”.
Note: We should always remember that whenever we have a positive power we can easily convert it into negative power but it will also render the reciprocal of the number instead of the original number this specific law of exponent is written in the below written formula,
$ {a^y} = \dfrac{1}{{{a^{ - y}}}} $
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

What are the 12 elements of nature class 8 chemistry CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Full form of STD, ISD and PCO

Convert 40circ C to Fahrenheit A 104circ F B 107circ class 8 maths CBSE

Advantages and disadvantages of science


