What is the relation between Wavelength and Refractive index.
Answer
586.2k+ views
Hint: In order to answer the above question, we will first define the term wavelength and refractive index. We will also write the equation for the following. We will understand the terms and try to find the relation or an equation connecting these two terms.
Complete step by step solution:
As we all know, the bending of a ray of light as it passes through one medium and through another is measured by the refractive index, also known as the index of refraction. If $i$ is the angle of incidence of a ray in vacuum (the angle between the incoming ray and the natural, which is perpendicular to the surface of a medium), and $r$ is the angle of refraction (angle between the ray in the medium and the normal), The refractive index $n$ is equal to the ratio of the sine of the angle of incidence to the sine of the angle of refraction; in other words,
$n=\dfrac{\sin \left( i \right)}{\sin \left( r \right)}$
The refractive index can also be stated as the velocity of light $c$ of a given wavelength in empty space divided by the velocity of light $v$ in a material,
$n=\dfrac{c}{v}$
Now, the wavelength of a wave is the distance between consecutive crests, especially the points of an electromagnetic wave. Wavelength and frequency are inextricably linked. The shorter the wavelength, the higher the frequency. Since all light waves travel at the same speed through a vacuum, the number of wave crests moving by a given point per second is determined by the wavelength.
The Wavelength is represented by the symbol $\lambda $. Any wave's Wavelength Formula is given by
$\lambda =\dfrac{v}{f}$
The wavelength is measured in metres, the velocity is measured in metres per second, and the frequency is measured in hertz.
Now, if we look at both the formulas, i.e., the formula of the refractive index of a material and the formula of the wavelength, we can write
$\lambda =\dfrac{c}{nf}$ because $\left[ n=\dfrac{c}{v} \right]$
Therefore, we can conclude that the wavelength is inversely proportional to the refractive index of the material in which the wave is travelling.
Note:
It is very important to note here that the frequency of the wave will also change inversely to the wavelength. If the wavelength of the wave is shortened, it implies that the frequency will be increased as the number of cycles completed in a unit interval of time will be increased.
Complete step by step solution:
As we all know, the bending of a ray of light as it passes through one medium and through another is measured by the refractive index, also known as the index of refraction. If $i$ is the angle of incidence of a ray in vacuum (the angle between the incoming ray and the natural, which is perpendicular to the surface of a medium), and $r$ is the angle of refraction (angle between the ray in the medium and the normal), The refractive index $n$ is equal to the ratio of the sine of the angle of incidence to the sine of the angle of refraction; in other words,
$n=\dfrac{\sin \left( i \right)}{\sin \left( r \right)}$
The refractive index can also be stated as the velocity of light $c$ of a given wavelength in empty space divided by the velocity of light $v$ in a material,
$n=\dfrac{c}{v}$
Now, the wavelength of a wave is the distance between consecutive crests, especially the points of an electromagnetic wave. Wavelength and frequency are inextricably linked. The shorter the wavelength, the higher the frequency. Since all light waves travel at the same speed through a vacuum, the number of wave crests moving by a given point per second is determined by the wavelength.
The Wavelength is represented by the symbol $\lambda $. Any wave's Wavelength Formula is given by
$\lambda =\dfrac{v}{f}$
The wavelength is measured in metres, the velocity is measured in metres per second, and the frequency is measured in hertz.
Now, if we look at both the formulas, i.e., the formula of the refractive index of a material and the formula of the wavelength, we can write
$\lambda =\dfrac{c}{nf}$ because $\left[ n=\dfrac{c}{v} \right]$
Therefore, we can conclude that the wavelength is inversely proportional to the refractive index of the material in which the wave is travelling.
Note:
It is very important to note here that the frequency of the wave will also change inversely to the wavelength. If the wavelength of the wave is shortened, it implies that the frequency will be increased as the number of cycles completed in a unit interval of time will be increased.
Recently Updated Pages
Differentiate between voluntary action and reflex class 10 biology CBSE

The uses of bleaching powder are A It is used bleaching class 10 chemistry CBSE

Fill in the blanks with abstract nouns of the words class 10 english CBSE

How many threedigit numbers are there class 10 maths CBSE

What is a reflex arc class 10 biology CBSE

Construct a square whose diagonal is 6cm Measure the class 10 maths CBSE

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

Which Indian city is known as "The Temple City"?

10 examples of evaporation in daily life with explanations

What is the full form of POSCO class 10 social science CBSE

The highest dam in India is A Bhakra dam B Tehri dam class 10 social science CBSE

Make a sketch of the human nerve cell What function class 10 biology CBSE

