
What is the relation between rate constant and activation energy?
Answer
506.7k+ views
Hint: We know that the Arrhenius condition is an equation for the temperature reliance of response rates. The condition was proposed by Svante Arrhenius in \[1889\] , in view of crafted by Dutch physicist Jacobs Henricus van 't Hoff who had noted in \[1884\] that the van 't Hoff condition for the temperature reliance of harmony constants recommends such a recipe for the paces of both forward and turn around responses. This condition has a huge and significant application in deciding pace of compound responses and for estimation of energy of actuation. Arrhenius gave an actual defense and translation for the recipe.
Complete answer:
As indicated by the Arrhenius condition, the connection between rate steady and actuation energy is given as
\[k = A{e^{\dfrac{{{E_0}}}{{RT}}}}\]
Here, k is the rate steady
A is the recurrence factor
\[{E_0}\] is the actuation energy
R is the gas steady
T is the temperature
Note:
Both the Arrhenius enactment energy and the rate constant k are tentatively decided, and address plainly visible response explicit boundaries that are not just identified with edge energies and the accomplishment of individual impacts at the atomic level. Think about a specific crash (a rudimentary response) between atoms A and B. The crash point, the general translational energy, the interior (especially vibrational) energy will all decide the opportunity that the impact will create an item atom AB. Plainly visible estimations of E and k are the consequence of numerous individual impacts with varying crash boundaries. To test response rates at atomic level, tests are directed under close collision conditions and this subject is frequently called subatomic response dynamics. Another circumstance where the clarification of the Arrhenius condition boundaries misses the mark is in heterogeneous catalysis, particularly for responses that show Langmuir-Hinshelwood energy. Plainly, particles on surfaces don't "impact" straightforwardly, and a basic subatomic cross-segment doesn't matter here. All things being equal, the pre-remarkable factor mirrors the movement across the surface towards the dynamic site.
Complete answer:
As indicated by the Arrhenius condition, the connection between rate steady and actuation energy is given as
\[k = A{e^{\dfrac{{{E_0}}}{{RT}}}}\]
Here, k is the rate steady
A is the recurrence factor
\[{E_0}\] is the actuation energy
R is the gas steady
T is the temperature
Note:
Both the Arrhenius enactment energy and the rate constant k are tentatively decided, and address plainly visible response explicit boundaries that are not just identified with edge energies and the accomplishment of individual impacts at the atomic level. Think about a specific crash (a rudimentary response) between atoms A and B. The crash point, the general translational energy, the interior (especially vibrational) energy will all decide the opportunity that the impact will create an item atom AB. Plainly visible estimations of E and k are the consequence of numerous individual impacts with varying crash boundaries. To test response rates at atomic level, tests are directed under close collision conditions and this subject is frequently called subatomic response dynamics. Another circumstance where the clarification of the Arrhenius condition boundaries misses the mark is in heterogeneous catalysis, particularly for responses that show Langmuir-Hinshelwood energy. Plainly, particles on surfaces don't "impact" straightforwardly, and a basic subatomic cross-segment doesn't matter here. All things being equal, the pre-remarkable factor mirrors the movement across the surface towards the dynamic site.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

10 examples of friction in our daily life

