Relation between kinetic energy(E) and RMS speed is given by:
A. \[\mu = {(\dfrac{{2E}}{m})^{1/2}}\]
B. \[\mu = {(\dfrac{{3E}}{{2m}})^{1/2}}\]
C. \[\mu = {(\dfrac{E}{{2m}})^{1/2}}\]
D. \[\mu = {(\dfrac{E}{{3m}})^{1/2}}\]
Answer
633.3k+ views
Hint: According to the kinetic molecular theory of gases, the average kinetic energy of molecules is directly proportional to the absolute temperature of the gas (\[K.E.\alpha T\] ). This can be represented by the following equation:
\[K.E. = \dfrac{3}{2}kT\]
K.E. represents Kinetic energy(average)
K represents Boltzmann constant
T represents Absolute temperature
Boltzmann constant is gas constant R divided by the Avogadro’s constant.
Kinetic energy is related to root mean square velocity by the following equation:
\[K.E. = \dfrac{1}{2}m{\mu ^2}\]
M represents mass
\[\mu \] represents Root mean square speed
K.E. represents Kinetic energy(average)
Complete step by step answer:
From the hint above we can see that: \[K.E. = \dfrac{3}{2}kT\] (equation 1)
We also know that root mean square velocity is given as: \[\mu = \sqrt {\dfrac{{3kT}}{m}} \] (equation 2)
Root mean square velocity can be defined as the square root of the average of the square of the velocity. When we measure the velocity of a particle at a given time it leads to a large distribution of values. Even the particles are moving in different directions so the velocity could be zero as some particles are moving slowly, and some are moving quickly. To properly assess the average velocity, the average of squares of velocities is taken and then the square root of that value is taken. This is defined as the root mean square velocity.
\[ \Rightarrow {\mu ^2} = \dfrac{{3kT}}{m}\] (Squaring both the sides in the above equation)
From equation 1
\[3kT = 2K.E.\]
Substituting this value in equation 2
\[\mu = \sqrt {\dfrac{{2K.E.}}{m}} \]
So, the correct answer is Option A.
Note: Gaseous particles move at random speeds in random directions. The Maxwell-Boltzmann distribution describes the average speeds of a collection of gaseous particles at a time. The average velocity of gases are generally expressed in the form of root mean square average value.
\[K.E. = \dfrac{3}{2}kT\]
K.E. represents Kinetic energy(average)
K represents Boltzmann constant
T represents Absolute temperature
Boltzmann constant is gas constant R divided by the Avogadro’s constant.
Kinetic energy is related to root mean square velocity by the following equation:
\[K.E. = \dfrac{1}{2}m{\mu ^2}\]
M represents mass
\[\mu \] represents Root mean square speed
K.E. represents Kinetic energy(average)
Complete step by step answer:
From the hint above we can see that: \[K.E. = \dfrac{3}{2}kT\] (equation 1)
We also know that root mean square velocity is given as: \[\mu = \sqrt {\dfrac{{3kT}}{m}} \] (equation 2)
Root mean square velocity can be defined as the square root of the average of the square of the velocity. When we measure the velocity of a particle at a given time it leads to a large distribution of values. Even the particles are moving in different directions so the velocity could be zero as some particles are moving slowly, and some are moving quickly. To properly assess the average velocity, the average of squares of velocities is taken and then the square root of that value is taken. This is defined as the root mean square velocity.
\[ \Rightarrow {\mu ^2} = \dfrac{{3kT}}{m}\] (Squaring both the sides in the above equation)
From equation 1
\[3kT = 2K.E.\]
Substituting this value in equation 2
\[\mu = \sqrt {\dfrac{{2K.E.}}{m}} \]
So, the correct answer is Option A.
Note: Gaseous particles move at random speeds in random directions. The Maxwell-Boltzmann distribution describes the average speeds of a collection of gaseous particles at a time. The average velocity of gases are generally expressed in the form of root mean square average value.
Recently Updated Pages
Which will be the least stable resonating structure class 11 chemistry CBSE

How many 5 digit telephone numbers can be construc-class-11-maths-CBSE

How do you find the angle of the resultant vector class 11 physics CBSE

Draw labelled diagram of the following i Gram seed class 11 biology CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

What is the need and importance of classification class 11 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

The teeth used for biting and cutting food are called class 11 biology CBSE

