
Reduce the following equations into slope -intercept form and find their slopes and the $ y $ -intercepts.
A. $ x + 7y = 0 $ ,
B. $ 6x + 3y - 5 = 0 $ ,
C. $ y = 0 $ .
Answer
590.1k+ views
Hint: First to find the slope-intercept form the formula for the slope-intercept form is the value of $ y $ - axis is equal to product of slope and $ x $ -axis and intercept. So need to write all the above equations in the slope intercept form.
Complete step-by-step answer:
Given:
For the first problem we have the equation is $ x + 7y = 0 $ .
For the second problem we have the equation is $ 6x + 3y - 5 = 0 $ .
For the third problem we have the equation is $ y = 0 $ .
The general formula for the slope – intercept form is $ y = mx + c $ .
Where $ m $ is the slope and $ c $ is the intercept.
i)
The given equation is $ x + 7y = 0 $ .
Now, we will add $ - 7y $ both sides to the above equation we obtain,
$ x + 7y - 7y = 0 - 7y $
Since $ 7y $ and $ - 7y $ get cancelled we obtain,
$ x = - 7y $
Multiply $ - 1 $ both sides to the above equation,
$ 7y = - x $
Then, multiply both sides by $ \dfrac{1}{7} $ we obtain,
$ y = - \dfrac{x}{7} + 0 $
The slope for the above equation is $ m = \dfrac{{ - 1}}{7} $ .
The intercept for the equation is $ 0 $ .
The slope -intercept form for the equation $ x + 7y = 0 $ is $ y = - \dfrac{x}{7} + 0 $ .
ii)
The given equation is $ 6x + 3y - 5 = 0 $ .
Adding $ - 3y $ both sides to the above equation we obtain,
$ 6x + 3y - 3y - 5 = - 3y $
Since $ 3y $ nd $ - 3y $ get cancelled we obtain,
$ 6x - 5 = - 3y $
Multiply $ - 1 $ both sides to the above equation,
$ 3y = - 6x + 5 $
Then, multiply both sides by $ \dfrac{1}{3} $ we obtain,
$ y = - \dfrac{{6x}}{3} + \dfrac{5}{3} $
The slope for the above equation is $ m = - \dfrac{6}{3} $ .
The intercept for the equation is $ \dfrac{5}{3} $ .
The slope - intercept form for the equation $ 6x + 3y - 5 = 0 $ is $ y = - \dfrac{{6x}}{3} + \dfrac{5}{3} $ .
iii)
The slope -intercept form is $ y = 0 $ .
Where, $ m = 0 $ and intercept is $ 0 $ .
Note: If $ x = 0 $ then in the slope-intercept form the slope will be $ 1 $ and intercept is $ 0 $ . If the slope is not given, then determine the slope and intercept and substitute in the general formula.
Complete step-by-step answer:
Given:
For the first problem we have the equation is $ x + 7y = 0 $ .
For the second problem we have the equation is $ 6x + 3y - 5 = 0 $ .
For the third problem we have the equation is $ y = 0 $ .
The general formula for the slope – intercept form is $ y = mx + c $ .
Where $ m $ is the slope and $ c $ is the intercept.
i)
The given equation is $ x + 7y = 0 $ .
Now, we will add $ - 7y $ both sides to the above equation we obtain,
$ x + 7y - 7y = 0 - 7y $
Since $ 7y $ and $ - 7y $ get cancelled we obtain,
$ x = - 7y $
Multiply $ - 1 $ both sides to the above equation,
$ 7y = - x $
Then, multiply both sides by $ \dfrac{1}{7} $ we obtain,
$ y = - \dfrac{x}{7} + 0 $
The slope for the above equation is $ m = \dfrac{{ - 1}}{7} $ .
The intercept for the equation is $ 0 $ .
The slope -intercept form for the equation $ x + 7y = 0 $ is $ y = - \dfrac{x}{7} + 0 $ .
ii)
The given equation is $ 6x + 3y - 5 = 0 $ .
Adding $ - 3y $ both sides to the above equation we obtain,
$ 6x + 3y - 3y - 5 = - 3y $
Since $ 3y $ nd $ - 3y $ get cancelled we obtain,
$ 6x - 5 = - 3y $
Multiply $ - 1 $ both sides to the above equation,
$ 3y = - 6x + 5 $
Then, multiply both sides by $ \dfrac{1}{3} $ we obtain,
$ y = - \dfrac{{6x}}{3} + \dfrac{5}{3} $
The slope for the above equation is $ m = - \dfrac{6}{3} $ .
The intercept for the equation is $ \dfrac{5}{3} $ .
The slope - intercept form for the equation $ 6x + 3y - 5 = 0 $ is $ y = - \dfrac{{6x}}{3} + \dfrac{5}{3} $ .
iii)
The slope -intercept form is $ y = 0 $ .
Where, $ m = 0 $ and intercept is $ 0 $ .
Note: If $ x = 0 $ then in the slope-intercept form the slope will be $ 1 $ and intercept is $ 0 $ . If the slope is not given, then determine the slope and intercept and substitute in the general formula.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

10 examples of friction in our daily life

