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Reaction of $HN{O_3}$ (conc) with I,S,P and C gives respectively:
A. $HI{O_3}$,${H_2}S{O_4}$,${H_3}P{O_4}$,$C{O_2}$
B. $HI{O_3}$,${H_2}S{O_4}$,${H_3}P{O_3}$,$C{O_2}$
C. ${I _3}{O_5}$,${H_2}S{O_4}$,${H_3}P{O_4}$,$CO$
D. ${I_2}{O_5}$,$S{O_2}$,${H_3}P{O_4}$,$C{O_2}$

Answer
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Hint: We have to know that when acids are reacted with non-metals we get oxy acids, with the liberation of gas. Oxy-acids are compounds that contain hydrogen, oxygen and one other element.

Complete step by step answer:
We know that inorganic compounds that contain hydrogen, oxygen, and one other element is known as oxy-acids. We can identify oxy acid by the presence of hydrogen in the compound’s formula. The second part of the formula contains a polyatomic ion containing oxygen.
We have to know that hydrogen is an oxy-acid that is not specifically designated in the name of acid. The presence of hydrogen in the compound is expressed by the word acid in the name of the acid.
So, when we react with nitric acid $HN{O_3}$ with iodine we get iodic acid. Iodic acid is an oxy acid of iodine. Along with iodic acid, nitrogen dioxide and water are also formed. We can write this reaction as,
${I_2} + 10HN{O_3} \to 2HI{O_3} + 10N{O_2} + 4{H_2}O$
When we react with nitric acid $HN{O_3}$ with sulfur we get sulfuric acid. Sulfuric acid is an oxy acid of sulfur. Along with sulfuric acid, nitrogen dioxide and water are also formed. We can write this reaction as,
$S + 6HN{O_3} \to {H_2}S{O_4} + 6N{O_2} + 2{H_2}O$
When we react with nitric acid $HN{O_3}$ with phosphorus we get phosphoric acid. Phosphoric acid is an oxy acid of phosphorus. Along with phosphoric acid, nitrogen dioxide and water are also formed. We can write this reaction as,
$P + 10HN{O_3} \to 2{H_3}P{O_4} + 10N{O_2} + 2{H_2}O$
When we react with nitric acid $HN{O_3}$ with carbon we get carbonic acid. Carbonic acid is an oxy acid of carbon and is an unstable stable. Along with carbonic acid, nitrogen dioxide is also formed. Due to its unstable nature, carbonic acid decomposes into carbon dioxide and water. We can write this reaction as,
$C + 4HN{O_3} \to C{O_2} + 4N{O_2} + 2{H_2}O$
The acid formed from the reaction of nitric acid with iodine is $HI{O_3}$.
The acid formed from the reaction of nitric acid with sulfur is ${H_2}S{O_4}$.
The acid formed from the reaction of nitric acid with phosphorus is ${H_3}P{O_4}$.
The product from reaction of nitric acid with carbon is $C{O_2}$.

Therefore, the option (A) is correct.

Note:
We have to know that oxy-acids dissociate into hydrogen ions and anions of the acid. Some of the organic oxy-acids are carboxylic acids and phenols. Chromic acid, Ferric acid, Nitrous acid, metaphosphoric acid are examples of inorganic oxy-acids.