Question

How can the reaction
$KBr+AgN{{O}_{3}}\to AgBr+KN{{O}_{3}}$ be classified?

Answer 1

Hint In a reaction, if the displacement of ions takes place, then the reaction is called displacement reaction. If one ion replaces then it is single displacement and if two ions displace then it is double displacement. In any reaction, there is the formation of precipitate then it is called a precipitation reaction.

Complete step by step answer:
The equation given in the question is:
$KBr+AgN{{O}_{3}}\to AgBr+KN{{O}_{3}}$
So, the potassium bromide reacts with silver nitrate to form silver bromide and potassium nitrate. All the compounds are ionic compounds because all of them are made up of ions. In potassium bromide, the ions are ${{K}^{+}}$ and $B{{r}^{-}}$, in silver nitrate the ions are $A{{g}^{+}}$ and $NO_{3}^{-}$, in silver bromide the ions are $A{{g}^{+}}$ and $B{{r}^{-}}$, and in potassium nitrate the ions are ${{K}^{+}}$ and $NO_{3}^{-}$
In this reaction, both the ions of reactants have changed, i.e., in $KBr$, the potassium ion is replaced with silver ion and in $AgN{{O}_{3}}$, the silver ion is replaced with potassium ion. Since two ions are being replaced with each other, we can classify this reaction as a double displacement reaction or we can also say that it is a double replacement reaction.
Also, both the reactant, i.e., potassium bromide and silver nitrate are soluble reactants, and when they react we get an insoluble product silver bromide which appears as a white precipitate. Since a precipitate is formed in this reaction we can also classify this reaction as a precipitate reaction.

So, the reaction is a double-displacement reaction and precipitate reaction.

Note: There are many other types of reaction like combination reaction in which two reactants form one product, decomposition reaction in which the reactant breaks into similar and simple molecules, etc.