
How do you rank the following measurements in order of increasing pressure:
4 kPa, .3 Pa, 16 $N/{{m}^{2}}$, 311 $N/{{m}^{2}}$?
Answer
535.8k+ views
Hint: Pressure is an important property of the solids, liquids, and gases which is used to describe it. There are many units in which we can describe the pressure like a bar, atmosphere, Pascal, Newton per meter square. 1 Pascal is equal to 1 Newton per meter square, and 1 kilo Pascal is equal to 1000 times Pascal.
Complete answer: The pressure is an important property of the solids, liquids, and gases which is used to describe it. There are many units in which we can describe the pressure like a bar, atmosphere, Pascal, Newton per meter square.
The SI unit of pressure is taken in Pascal which is written as Pa, and it is equal to the force exerted by 1 Newton on an area of 1${{m}^{2}}$.
We can relate the above as:
$1\text{ }Pa=1\text{ }N/{{m}^{2}}$
1 kiloPascal is equal to 1000 times Pascal, we can write it as:
1 kPa = 1000 Pa
The given values in the question are:
4 kPa, .3 Pa, 16 $N/{{m}^{2}}$, 311 $N/{{m}^{2}}$
Let us convert all the values into Pascal (Pa).
(i)- 4kPa- The given value is in KiloPascal, we can multiply it by 1000.
4 kPa = 4000 Pa
(ii)- .3 Pa- This value is in Pascal.
.3 Pa = 0.3 Pa
(iii)- 16 $N/{{m}^{2}}$- This value is in Newton per meter square, and it is equal to Pascal.
16 $N/{{m}^{2}}$ = 16 Pa
(iv)- 311 $N/{{m}^{2}}$- This value is in Newton per meter square, and it is equal to Pascal.
311 $N/{{m}^{2}}$ = 311 Pa
The increasing order will be: 0.3 Pa < 16 Pa < 311 Pa < 4000 Pa.
Note: There are many other units like atmosphere (atm), bar, torr, etc in which we can define the pressure. Some of the conversion are given below:
1 atm = 760 torr
1 atm = 1.01325 bar
1 bar = 0.987 atm
Complete answer: The pressure is an important property of the solids, liquids, and gases which is used to describe it. There are many units in which we can describe the pressure like a bar, atmosphere, Pascal, Newton per meter square.
The SI unit of pressure is taken in Pascal which is written as Pa, and it is equal to the force exerted by 1 Newton on an area of 1${{m}^{2}}$.
We can relate the above as:
$1\text{ }Pa=1\text{ }N/{{m}^{2}}$
1 kiloPascal is equal to 1000 times Pascal, we can write it as:
1 kPa = 1000 Pa
The given values in the question are:
4 kPa, .3 Pa, 16 $N/{{m}^{2}}$, 311 $N/{{m}^{2}}$
Let us convert all the values into Pascal (Pa).
(i)- 4kPa- The given value is in KiloPascal, we can multiply it by 1000.
4 kPa = 4000 Pa
(ii)- .3 Pa- This value is in Pascal.
.3 Pa = 0.3 Pa
(iii)- 16 $N/{{m}^{2}}$- This value is in Newton per meter square, and it is equal to Pascal.
16 $N/{{m}^{2}}$ = 16 Pa
(iv)- 311 $N/{{m}^{2}}$- This value is in Newton per meter square, and it is equal to Pascal.
311 $N/{{m}^{2}}$ = 311 Pa
The increasing order will be: 0.3 Pa < 16 Pa < 311 Pa < 4000 Pa.
Note: There are many other units like atmosphere (atm), bar, torr, etc in which we can define the pressure. Some of the conversion are given below:
1 atm = 760 torr
1 atm = 1.01325 bar
1 bar = 0.987 atm
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