Question

Rahul earns Rs.6000 per month. He saves Rs.2000, what percentage of his earning is saved?

Answer 1

Hint: We are given a question stating the salary of Rahul and also the amount that he saves each month. We are asked to find the percentage of the earning that is getting saved. So, we are given the value of total salary and also the value of the amount being saved. We will first calculate the ratio of the amount being saved and the total salary and then we will multiply the obtained by 100. Hence, we will have the percentage of the earnings being saved.

Complete step-by-step solution:
According to the given question, we are given the monthly salary of Rahul and we are also given the value of the amount being saved from the salary every month. We are asked to find the percentage of his earnings that is being saved.
We will first write down the given values, we have,
The total salary of the Rahul = Rs.6000
The amount Rahul saves every month = Rs.2000
We will first calculate the ratio of the amount that Rahul saves every month and the total salary and so we get,
\[\dfrac{\text{Amount Rahul saves every month}}{\text{Total salary of Rahul}}\]
\[\Rightarrow \dfrac{2000}{6000}\]
We will now reduce the above ratio as simple as possible and we get,
\[\Rightarrow \dfrac{2}{6}\]
\[\Rightarrow \dfrac{1}{3}\]
We will now multiply the above ratio by 100 and we get,
\[\Rightarrow \dfrac{1}{3}\times 100\]
Now, dividing 100 by 3, we get the value as,
\[\Rightarrow \dfrac{100}{3}\]
So, we get the value as,
\[\Rightarrow 33.33\%\]
Therefore, the percentage of Rahul’s earnings being saved is \[33.33\%\].

Note: While finding the percentage, the fraction should always be a proper fraction. There are two types of fraction, one is proper fraction and the other is improper fraction. A proper fraction is a fraction having the denominator greater than the numerator. An improper fraction refers to a fraction having numerator greater than the denominator.