Question

Raghu is \[21\] years old and Kavitha is \[22\] years old Write the sum of their ages in Roman system
 A) $XXXIII$
B) $XLIII$
C) $LIII$
D) $XCIII$

Answer 1

Hint: To solve the above we need to show to take into consideration of roman numeral property that if the numeral is arranged in increasing order of the numeral values then they are added but if they are arranged in such way that lower order numeral is standing first and the other numeral have the higher value then the first then they are subtracted

Complete step-by-step answer:
First let us consider all the example by considering the hint in mind
So, the result of the numeral value must be $21 + 22 = 43$
Let us first consider the first option
$XXXIII$
Above
$X = 10$
And
$I = 1$
So, as we can see that the numerals are arranged in ascending order that means the specific values will be added
$XXXIII = 10 + 10 + 10 + 1 + 1 + 1 + 1 = 34$
This is not the required result
Moving forward to the next option
$XLIII$
The above have the value
$X = 10,L = 50,I = 1$
As we can say that the roman values is not arranged in the ascending order that means the smaller value which is present in front of the greater value will be subtracted then in such case the required result will be
$XLIII = - 10 + 50 + 1 + 1 + 1 = 43$
So, the above satisfy the required result
Now, let us also check the other options
$LIII$
Having the value to be
$L = 50,I = 1$
So, the required total will be
$LIII = 50 + 1 + 1 + 1 = 53$
Hence, the above is not the required result
Now, moving forward to the last option we get
$XCIII$
The value for above are
$X = 10,C = 100 = 50,I = 1$
They are not arranged in the ascending order then the result will be
$XCIII = - 10 + 100 + 1 + 1 + 1 = 93$
Hence, it is not the required result

Option B is the correct option

Note: We have noted that in the above question the numeral addition is dependent on the numeral values in such case we need to first see which numeral is arranged in such a order to check the result, if the numeral is ascending then the result will be added and not then different way to determine the value of numeral exists.