
Question: consider the table given below:
Marks $0 - 10$ $10 - 20$ $20 - 30$ $30 - 40$ $40 - 50$ $50 - 60$ students $12$ $18$ $27$ $20$ $17$ $6$
The arithmetic mean of the marks given above is:
A. $18$
B. $28$
C. $27$
D. $6$
Marks | $0 - 10$ | $10 - 20$ | $20 - 30$ | $30 - 40$ | $40 - 50$ | $50 - 60$ |
students | $12$ | $18$ | $27$ | $20$ | $17$ | $6$ |
Answer
503.7k+ views
Hint:
Here we are given that the marks are as the class interval and the number of students represent the frequency then the arithmetic mean will be given by the formula:
$\dfrac{{\sum {{x_i}{f_i}} }}{{\sum {{f_i}} }}$ and here ${x_i}$ is the average of the upper and lower limit of the class interval.
Complete step by step solution:
Here we are given the range of marks which are obtained by the students as given below
So here the frequency of $0 - 10$ marks is $12$ that means there are twelve students whose marks are between $0,10$ and similarly we are given the frequency of all the marks obtained that is the marks are obtained by how many number of students and the ranges are given that in which range the marks are obtained by how many number of students?
The mean is given by the formula $\dfrac{{\sum {{x_i}{f_i}} }}{{\sum {{f_i}} }}$ and here ${x_i}$ is the average of the upper and lower limit of the class interval
So ${x_1} = \dfrac{{0 + 10}}{2} = 5$
$
{x_2} = \dfrac{{10 + 20}}{2} = 15 \\
{x_3} = \dfrac{{20 + 30}}{2} = 25 \\
{x_4} = \dfrac{{30 + 40}}{2} = 35 \\
{x_5} = \dfrac{{40 + 50}}{2} = 45 \\
{x_6} = \dfrac{{50 + 60}}{2} = 55 \\
$
So here mean$ = \dfrac{{\sum {{x_i}{f_i}} }}{{\sum {{f_i}} }}$
$
= \dfrac{{{x_1}{f_1} + {x_2}{f_2} + {x_3}{f_3} + {x_4}{f_4} + {x_5}{f_5} + {x_6}{f_6}}}{{{f_1} + {f_2} + {f_3} + {f_4} + {f_5} + {f_6}}} \\
= \dfrac{{5(12) + 18(15) + 27(25) + 20(35) + 17(45) + 6(55)}}{{12 + 18 + 27 + 20 + 17 + 6}} \\
= \dfrac{{60 + 270 + 675 + 700 + 765 + 330}}{{100}} = 28 \\
$
Therefore mean is $28$.
Note:
Arithmetic mean of the two numbers a and b is given by the formula $\dfrac{{a + b}}{2}$ and the geometric mean is given by the formula $\sqrt {ab} $
Harmonic mean is given by the formula $\dfrac{{2ab}}{{a + b}}$
Here we are given that the marks are as the class interval and the number of students represent the frequency then the arithmetic mean will be given by the formula:
$\dfrac{{\sum {{x_i}{f_i}} }}{{\sum {{f_i}} }}$ and here ${x_i}$ is the average of the upper and lower limit of the class interval.
Complete step by step solution:
Here we are given the range of marks which are obtained by the students as given below
Marks | $0 - 10$ | $10 - 20$ | $20 - 30$ | $30 - 40$ | $40 - 50$ | $50 - 60$ |
students | $12$ | $18$ | $27$ | $20$ | $17$ | $6$ |
So here the frequency of $0 - 10$ marks is $12$ that means there are twelve students whose marks are between $0,10$ and similarly we are given the frequency of all the marks obtained that is the marks are obtained by how many number of students and the ranges are given that in which range the marks are obtained by how many number of students?
The mean is given by the formula $\dfrac{{\sum {{x_i}{f_i}} }}{{\sum {{f_i}} }}$ and here ${x_i}$ is the average of the upper and lower limit of the class interval
So ${x_1} = \dfrac{{0 + 10}}{2} = 5$
$
{x_2} = \dfrac{{10 + 20}}{2} = 15 \\
{x_3} = \dfrac{{20 + 30}}{2} = 25 \\
{x_4} = \dfrac{{30 + 40}}{2} = 35 \\
{x_5} = \dfrac{{40 + 50}}{2} = 45 \\
{x_6} = \dfrac{{50 + 60}}{2} = 55 \\
$
So here mean$ = \dfrac{{\sum {{x_i}{f_i}} }}{{\sum {{f_i}} }}$
$
= \dfrac{{{x_1}{f_1} + {x_2}{f_2} + {x_3}{f_3} + {x_4}{f_4} + {x_5}{f_5} + {x_6}{f_6}}}{{{f_1} + {f_2} + {f_3} + {f_4} + {f_5} + {f_6}}} \\
= \dfrac{{5(12) + 18(15) + 27(25) + 20(35) + 17(45) + 6(55)}}{{12 + 18 + 27 + 20 + 17 + 6}} \\
= \dfrac{{60 + 270 + 675 + 700 + 765 + 330}}{{100}} = 28 \\
$
Therefore mean is $28$.
Note:
Arithmetic mean of the two numbers a and b is given by the formula $\dfrac{{a + b}}{2}$ and the geometric mean is given by the formula $\sqrt {ab} $
Harmonic mean is given by the formula $\dfrac{{2ab}}{{a + b}}$
Recently Updated Pages
Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Why is the cell called the structural and functional class 12 biology CBSE

a Tabulate the differences in the characteristics of class 12 chemistry CBSE

Who discovered the cell and how class 12 biology CBSE

Pomato is a Somatic hybrid b Allopolyploid c Natural class 12 biology CBSE
