
Prove that in an isosceles triangle, the median to the base is also perpendicular.
Answer
591.3k+ views
Hint: Properties which must be known while solving this question are as follows: -
i) SSS (side side side ) congruence rule of triangle- In this two triangles are said to satisfy SSS congruent rule in which all three sides of one triangle are equal to the corresponding sides of another triangle.
ii) Median divides the line into two equal parts.
iii) Isosceles triangle has two equal base angles.
Complete step-by-step answer:
To prove: In an isosceles triangle median to the base is also perpendicular.
Proof: Let ABC be an isosceles triangle having AD as a median which divides side BC into two equal parts (BD=DC) making D as a midpoint, below is the figure mentioning that.
To proof median perpendicular we have to proof \[\angle ADB = \angle ADC\]
In $\Delta {ADB}$ and $\Delta{ADC}$
$AB = AC$ (Isosceles triangle given)
$BD = DC$ (Median divides BC into two equal parts)
$AD = AD$ (Common)
(SSS congruent rule)
$\therefore $ $\angle ADB = \angle ADC$ (By corresponding parts of congruent triangles)
Now let $\angle ADB = ADC = {x^ \circ }$
$\therefore $ $\angle ADB + \angle ADC = {180^ \circ }$ (Sum of angles on a straight line is ${180^ \circ }$ )
${x^ \circ } + {x^ \circ } = {180^ \circ }$
Solving for $x$,
$2{x^ \circ } = {180^ \circ }$
On simplifying the above equation, we get
${x^ \circ } = {90^ \circ }$
$\therefore $ $\angle ADB = \angle ADC = {90^ \circ }$
Hence it is proved that median to the base is also perpendicular.
Note:
Alternate method: To prove triangles congruency one can also use SAS (side angle side ) rule.
For example: $\Delta {ADB}$ and $\Delta{ADC}$
$AB = AC$ (Isosceles triangle given)
$\angle ABC = \angle ACD$ (Isosceles base angles equal)
$BD = DC$ (Median divides BC into two equal parts)
(SAS rule of congruency)
There are more congruent properties of a triangle:-
AAS (angle angle side) congruency – It states that when two angles and non included side of one triangle is equal to the corresponding two angles and non included side of another triangle then it is said to be AAS property of congruency.
ASA (angle side angle) congruency – It states that if two angles including side of one triangle are equal to corresponding two angles and including side of another triangle then it is said to be ASA congruency.
i) SSS (side side side ) congruence rule of triangle- In this two triangles are said to satisfy SSS congruent rule in which all three sides of one triangle are equal to the corresponding sides of another triangle.
ii) Median divides the line into two equal parts.
iii) Isosceles triangle has two equal base angles.
Complete step-by-step answer:
To prove: In an isosceles triangle median to the base is also perpendicular.
Proof: Let ABC be an isosceles triangle having AD as a median which divides side BC into two equal parts (BD=DC) making D as a midpoint, below is the figure mentioning that.
To proof median perpendicular we have to proof \[\angle ADB = \angle ADC\]
In $\Delta {ADB}$ and $\Delta{ADC}$
$AB = AC$ (Isosceles triangle given)
$BD = DC$ (Median divides BC into two equal parts)
$AD = AD$ (Common)
(SSS congruent rule)
$\therefore $ $\angle ADB = \angle ADC$ (By corresponding parts of congruent triangles)
Now let $\angle ADB = ADC = {x^ \circ }$
$\therefore $ $\angle ADB + \angle ADC = {180^ \circ }$ (Sum of angles on a straight line is ${180^ \circ }$ )
${x^ \circ } + {x^ \circ } = {180^ \circ }$
Solving for $x$,
$2{x^ \circ } = {180^ \circ }$
On simplifying the above equation, we get
${x^ \circ } = {90^ \circ }$
$\therefore $ $\angle ADB = \angle ADC = {90^ \circ }$
Hence it is proved that median to the base is also perpendicular.
Note:
Alternate method: To prove triangles congruency one can also use SAS (side angle side ) rule.
For example: $\Delta {ADB}$ and $\Delta{ADC}$
$AB = AC$ (Isosceles triangle given)
$\angle ABC = \angle ACD$ (Isosceles base angles equal)
$BD = DC$ (Median divides BC into two equal parts)
(SAS rule of congruency)
There are more congruent properties of a triangle:-
AAS (angle angle side) congruency – It states that when two angles and non included side of one triangle is equal to the corresponding two angles and non included side of another triangle then it is said to be AAS property of congruency.
ASA (angle side angle) congruency – It states that if two angles including side of one triangle are equal to corresponding two angles and including side of another triangle then it is said to be ASA congruency.
Recently Updated Pages
The stick and ball games played in England some 500 class 9 social science CBSE

The curved surface area of a frustum cone is 25pi mm2 class 9 maths CBSE

The cost of painting the curved surface area of a cone class 9 maths CBSE

Prove that the equation x2 + px 1 0 has real and distinct class 9 maths CBSE

What is the name of a parallelogram with all sides class 9 maths CBSE

If a b are coprime then a2b2 are a Coprime b Not coprime class 9 maths CBSE

Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Difference Between Plant Cell and Animal Cell

Which places in India experience sunrise first and class 9 social science CBSE

Name 10 Living and Non living things class 9 biology CBSE

What is the full form of pH?

Write the 6 fundamental rights of India and explain in detail

