Question

How many protons, neutrons, and electrons are in a silver atom, with a mass number of $108$?

Answer 1

Hint: For an atom Atomic number ($\text{Z}$) is always equal to the number of electrons or number of protons and Atomic mass ($\text{A}$) is equal to the sum of the number of neutrons and protons.

Complete answer:
Silver is placed at the 4d series of the transition metals in the d-block and its atomic number is equal to $47$.
-Relation between atomic number, electrons and protons are described as follow:
Atomic number ($\text{Z}$) = No. of electrons = No. of protons
From above relation it is clear that, number of electrons which are present outside the nucleus in the orbital of silver atom is equal to $47$ and number of protons which are present inside the nucleus is also equal to $47$, because the atomic number ($\text{Z}$) of silver is $47$.
-Relation between atomic mass, protons and neutrons are described as follow:
Atomic mass ($\text{A}$) = No. of protons + No. of neutrons
It is given that, atomic mass of silver = $108$
And also we know that number of protons in silver = $47$
So, number of neutrons = Atomic mass ($\text{A}$) - No. of protons
No. of neutrons = $108-47=61$.
Hence $61$ neutrons, and $47$ electrons and protons are present in the silver atom.

Note:
Here some of you may count the number of electrons always equal to the atomic number of that atom, which is not always correct because if an atom present in the form of ion then the number of electrons are not equal to the atomic number of that atom.