Question

How many products are obtained on the ozonolysis of propene?

Answer 1

Hint: Mechanism of Ozonolysis reaction of the alkene. Ozonolysis gives carbonyl compounds as products. As we know there are 3 oxygen atoms present in the ozone molecule. Alkene or alkyne is converted into carbonyl compounds with the addition of ozone and a reducing agent.

Complete answer:
-We should first understand what an Ozonolysis reaction is. It is an organic reaction in which the unsaturated bonds of the double bonds of alkenes are cleaved by ozone from carbonyl compounds.
-We have the first step i.e. the addition of oxygen atoms from ozone. The oxygen gets added to the double bonds.
-Then, we can see that oxidative cleavage happens through the action of a reducing agent.
-In this question, propene is ozonolysis. 

The chemical reaction can be written as:
${{C}}{{{H}}_{{3}}}{{ = CH - C}}{{{H}}_{{2}}}{{ + }}{{{O}}_{{3}}} \to {{C}}{{{H}}_{{2}}}{{{rm O} + C}}{{{H}}_{{3}}}{{CHO}}$
-Here, oxygen gets added to the double bonds and oxidative cleavage happens.
-As we observe, there will be 2 products here, one is acetaldehyde, and the other is formaldehyde.
-In the ozonolysis reaction, it is easy to find the number of products because if a double bond is present and the hydrocarbons on both sides of the double bond are different, due to oxidative cleavage 2 different products will be formed.
-Therefore, the answer is 2.
-If the hydrocarbons on both sides of the double bond are the same, there will be 2 products which will be the same.
-In the last, we can conclude that on the ozonolysis of propene, the 2 products will be formed.

Note: If butene is treated with ozone, 2 products will be formed, but the products will be the same. $C{H_3}CH = CHC{H_3} + {O_3} \to C{H_3}CHO + C{H_3}CHO$. It differs for cycloalkenes. In ozonolysis, as we saw multiple carbon bonds will be cleaved to form a carbonyl compound.