
Probability of happening an event A is \[0.5\]and that of B is \[0.3\]. If A and B are mutually exclusive events, then the probability of happening neither A nor B is
A. \[0.6\]
B. \[0.2\]
C. \[0.21\]
D. None of these
Answer
495k+ views
Hint: The probability of two events, A and B, are given below. We wanted to know the chances of neither A nor B occurring. In probability, neither A nor B have a standard formula. We acquire the answer by substituting values from that standard formula.
Formula used:
Some formulas that we need to know to solve this problem:
\[P(A' \cap B') = 1 - P(A \cup B)\]
\[P(A \cup B) = P(A) + P(B) - P(A \cap B)\]
Complete step by step answer:
It is given that the probability of two events A and B are\[0.5\] \[\& \] \[0.3\]respectively and also these events are mutually exclusive.
We aim to find the probability of happening neither A nor B.
We know that there are several standard formulas to find the probability of events. We also have a formula for the probability of neither an event nor the other.
If there are two events A and B. Then, the probability of neither A nor B is given by
\[P(A' \cap B') = 1 - P(A \cup B)\]
But we don’t know the probability of A union B. Let us find this by using the formula
\[P(A \cup B) = P(A) + P(B) - P(A \cap B)\]
Since we already know the values of probability of A and probability of B, substitute them in the above formula.
\[P(A \cup B) = 0.5 + 0.3 - P(A \cap B)\]
Since it is given that events A and B are mutually exclusive events, we get
\[P(A \cup B) = 0.5 + 0.3 - 0\]
On simplifying this we get
\[P(A \cup B) = 0.8\]
Now we got the value of the probability of A union B\[P(A \cup B)\]. Let us substitute it in the formula\[P(A' \cap B') = 1 - P(A \cup B)\].
\[P(A' \cap B') = 1 - 0.8\]
On simplifying this we get
\[P(A' \cap B') = 0.2\]
Thus, we got the probability of happening neither A nor B is \[0.2\]
Let us see the options, option (1) \[0.6\]is not the correct answer since we got that \[0.2\]from our calculation.
Option (2) \[0.2\]is the correct answer as we got the same value in our calculation.
Option (3) \[0.21\]is not the correct answer since we got that \[0.2\]from our calculation.
Option (4) None of these is the incorrect answer as we got option (2) as a correct answer.
Hence, option (2) \[0.2\]is the correct option.
Note: Mutually exclusive events imply that the activities are discontinuous, that there will be no intersection between them. As a result, in the formula above, we substituted 0 for the chance of A intersection B.
Formula used:
Some formulas that we need to know to solve this problem:
\[P(A' \cap B') = 1 - P(A \cup B)\]
\[P(A \cup B) = P(A) + P(B) - P(A \cap B)\]
Complete step by step answer:
It is given that the probability of two events A and B are\[0.5\] \[\& \] \[0.3\]respectively and also these events are mutually exclusive.
We aim to find the probability of happening neither A nor B.
We know that there are several standard formulas to find the probability of events. We also have a formula for the probability of neither an event nor the other.
If there are two events A and B. Then, the probability of neither A nor B is given by
\[P(A' \cap B') = 1 - P(A \cup B)\]
But we don’t know the probability of A union B. Let us find this by using the formula
\[P(A \cup B) = P(A) + P(B) - P(A \cap B)\]
Since we already know the values of probability of A and probability of B, substitute them in the above formula.
\[P(A \cup B) = 0.5 + 0.3 - P(A \cap B)\]
Since it is given that events A and B are mutually exclusive events, we get
\[P(A \cup B) = 0.5 + 0.3 - 0\]
On simplifying this we get
\[P(A \cup B) = 0.8\]
Now we got the value of the probability of A union B\[P(A \cup B)\]. Let us substitute it in the formula\[P(A' \cap B') = 1 - P(A \cup B)\].
\[P(A' \cap B') = 1 - 0.8\]
On simplifying this we get
\[P(A' \cap B') = 0.2\]
Thus, we got the probability of happening neither A nor B is \[0.2\]
Let us see the options, option (1) \[0.6\]is not the correct answer since we got that \[0.2\]from our calculation.
Option (2) \[0.2\]is the correct answer as we got the same value in our calculation.
Option (3) \[0.21\]is not the correct answer since we got that \[0.2\]from our calculation.
Option (4) None of these is the incorrect answer as we got option (2) as a correct answer.
Hence, option (2) \[0.2\]is the correct option.
Note: Mutually exclusive events imply that the activities are discontinuous, that there will be no intersection between them. As a result, in the formula above, we substituted 0 for the chance of A intersection B.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

