
Predict in which of the following entropy decreases:
A. A liquid crystallizes into a solid.
B. Temperature of a crystalline solid raised from \[0K\] to \[115K\]
C. \[2NaHC{{O}_{2}}\left( s \right)\to N{{a}_{2}}C{{O}_{3}}\left( s \right)+C{{O}_{2}}\left( g \right)+{{H}_{2}}O\left( g \right)\]
D. \[{{H}_{2}}\left( g \right)\to 2H\left( g \right)\]
Answer
564.9k+ views
Hint: When a small amount of heat ΔQ is added to a substance at temperature T, without changing its temperature appreciably, the entropy of the substance changes by When heat is removed, the entropy decreases, when heat is added the entropy increases. Entropy has units of Joules per Kelvin.
Complete step by step answer:
(a) Option 1st: When a liquid crystallizes into a solid, the molecule obtains an ordered state and hence, entropy decreases.
(b) Option 2nd: At \[0K\], the constituent particles are static and entropy is minimum. If temperature is raised to \[115K\], these begin to move and oscillate about their equilibrium positions in the lattice and the system becomes more disordered, hence entropy increases.
(c) Option 3rd:
\[2NaHC{{O}_{2}}\left( s \right)\to N{{a}_{2}}C{{O}_{3}}\left( s \right)+C{{O}_{2}}\left( g \right)+{{H}_{2}}O\left( g \right)\]
In this reaction, the reactant, NaHCO3 is a solid and it has low entropy. Among products, there are one solid and two gases. So, the products represent a condition of higher entropy.
(d) Option 4th:
\[{{H}_{2}}\left( g \right)\to 2H\left( g \right)\]
Here, one molecule of hydrogen gives two hydrogen atoms i.e. the number of particles increases leading to more disordered state. Two moles of H-atoms have higher entropy than one mole of hydrogen molecule.
So the correct option is A
Note:
A phase change from a liquid to a solid (i.e. freezing), or from a gas to a liquid (i.e. condensation) results in decrease in the disorder of the substance, and a decrease in the entropy. The entropy of a framework relies upon its inward energy and its outer boundaries, for example, its volume. In as far as possible, this reality prompts a condition relating the adjustment in the inward energy U to changes in the entropy and the outside boundaries.
Complete step by step answer:
(a) Option 1st: When a liquid crystallizes into a solid, the molecule obtains an ordered state and hence, entropy decreases.
(b) Option 2nd: At \[0K\], the constituent particles are static and entropy is minimum. If temperature is raised to \[115K\], these begin to move and oscillate about their equilibrium positions in the lattice and the system becomes more disordered, hence entropy increases.
(c) Option 3rd:
\[2NaHC{{O}_{2}}\left( s \right)\to N{{a}_{2}}C{{O}_{3}}\left( s \right)+C{{O}_{2}}\left( g \right)+{{H}_{2}}O\left( g \right)\]
In this reaction, the reactant, NaHCO3 is a solid and it has low entropy. Among products, there are one solid and two gases. So, the products represent a condition of higher entropy.
(d) Option 4th:
\[{{H}_{2}}\left( g \right)\to 2H\left( g \right)\]
Here, one molecule of hydrogen gives two hydrogen atoms i.e. the number of particles increases leading to more disordered state. Two moles of H-atoms have higher entropy than one mole of hydrogen molecule.
So the correct option is A
Note:
A phase change from a liquid to a solid (i.e. freezing), or from a gas to a liquid (i.e. condensation) results in decrease in the disorder of the substance, and a decrease in the entropy. The entropy of a framework relies upon its inward energy and its outer boundaries, for example, its volume. In as far as possible, this reality prompts a condition relating the adjustment in the inward energy U to changes in the entropy and the outside boundaries.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

