
PQRS is a rhombus with \[\angle PQR = 58^\circ \]. Determine \[\angle PRS \].
Answer
602.7k+ views
Hint: The quadrilateral having all sides of equal length is called rhombus. The adjacent sides of a rhombus are supplementary. The diagonal of a rhombus is angular bisector.
Complete step-by-step answer:
Consider a rhombus \[PQRS\] inside of a circle as shown below.
Since, the adjacent sides of a rhombus are supplementary, it can be written as follows:
\[
\angle QRS + \angle PQR = 180^\circ \\
\angle QRS = 180^\circ - \angle PQR \\
\angle QRS = 180^\circ - 58^\circ \\
\angle QRS = 122^\circ \\
\]
Since, the diagonal of a rhombus is angular bisector, so the \[\angle PRS \] is half of the\[\angle QRS\].
\[
\angle PRS = \dfrac{{\angle QRS}}{2} \\
\angle PRS = \dfrac{{122^\circ }}{2} \\
\angle PRS = 61^\circ \\
\]
Thus, the value of the \[\angle PRS \] is \[61^\circ \].
Note: The adjacent sides of a rhombus are supplementary and the diagonal of a rhombus is angular bisector. These two properties should be known to students to solve this problem.
Complete step-by-step answer:
Consider a rhombus \[PQRS\] inside of a circle as shown below.
Since, the adjacent sides of a rhombus are supplementary, it can be written as follows:
\[
\angle QRS + \angle PQR = 180^\circ \\
\angle QRS = 180^\circ - \angle PQR \\
\angle QRS = 180^\circ - 58^\circ \\
\angle QRS = 122^\circ \\
\]
Since, the diagonal of a rhombus is angular bisector, so the \[\angle PRS \] is half of the\[\angle QRS\].
\[
\angle PRS = \dfrac{{\angle QRS}}{2} \\
\angle PRS = \dfrac{{122^\circ }}{2} \\
\angle PRS = 61^\circ \\
\]
Thus, the value of the \[\angle PRS \] is \[61^\circ \].
Note: The adjacent sides of a rhombus are supplementary and the diagonal of a rhombus is angular bisector. These two properties should be known to students to solve this problem.
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