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# Plot the following points on the same graph paper: $A(2,\dfrac{5}{2}),\,B( - \dfrac{3}{2},3),\,C(\dfrac{1}{2},\dfrac{3}{2})\,and\,D( - \dfrac{5}{2}, - \dfrac{1}{2})$

Last updated date: 17th Jun 2024
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For the point $A(2,\dfrac{5}{2})$ , the x-coordinate is $2$ and the y-coordinate is $\dfrac{5}{2}$ , both of the values are positive so point A lies in the first quadrant.
For the point $B( - \dfrac{3}{2},3)$ , the x-coordinate is $- \dfrac{3}{2}$ and the y-coordinate is $3$ , the value of x-coordinate is negative while that of y-coordinate is positive so point B lies in the second quadrant.
For the point $C(\dfrac{1}{2}, - \dfrac{3}{2})$ , the x-coordinate is $\dfrac{1}{2}$ and the y-coordinate is $- \dfrac{3}{2}$ , the value of y-coordinate is negative while that of x-coordinate is positive so point C lies in the fourth quadrant.
For the point $D( - \dfrac{5}{2}, - \dfrac{1}{2})$ , the x-coordinate is $- \dfrac{5}{2}$ and the y-coordinate is $- \dfrac{1}{2}$ , both of the values are negative so point D lies in the third quadrant.