Question

Percentage dissociation of \[PC{l_5}\] may be given as:
A. $4.04$
B. $40.4$
C. $44.0$
D. $0.404$

Answer 1

Hint: In the given question firstly we have to define the exact Percentage dissociation are they. Now after that we can use this information and do the step by step work of finding the Percentage dissociation of the ions through the formula of $\alpha = \dfrac{{{M_{tho}} - {M_{ob}}}}{{{M_{ob}}(n - 1)}}$ .

Complete step by step answer:
The given question statement asks about the entire process through which we would be able to get the proper and correct Percentage dissociation. So we have to explain what exactly is dissociation constant. Now by this we get the steps and use it to get the answer.
The Percent dissociation can range from \[0\% < {\text{ }}\alpha {\text{ }} < {\text{ }}100\% \] . Apart from that the Strong acids have a value of α that is equal to or nearly 100%; for weak acids, however, α can vary, depending on the acid’s strength.
Now for the process of obtaining Percentage dissociation of the of the question we need to follow these steps:
Step 1: Here we know that the formula we need for the finding of the Percentage dissociation which is mentioned by the sign of $\alpha $ , would be written as follows:
$\alpha = \dfrac{{{M_{tho}} - {M_{ob}}}}{{{M_{ob}}(n - 1)}}$
Step 2: Now we just have to use the values we know in this formula and then find the desired value for the question. Thus the respective values for the given question is ${M_{tho}} = 209$ and ${M_{ob}} = 149$ . Now we just have to put this in the formula and we will solve it to get the answer.
Step 3:
Here the value of $n = 2$ because of the formation of 2 ions on dissociation.
$\alpha = \dfrac{{{M_{tho}} - {M_{ob}}}}{{{M_{ob}}(n - 1)}}$
$\alpha = \dfrac{{209 - 149}}{{149(2 - 1)}}$
$\alpha = \dfrac{{60}}{{149}}$
$\alpha = 40$

So, the correct answer is Option B.

Note: Apart from that the Strong acids have a value of α that is equal to or nearly 100%; for weak acids, however, α can vary, depending on the acid’s strength. To determine percent dissociation, we first need to solve for the concentration of ${H^ + }$ .